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____ [38]
2 years ago
10

BRAINLIESTTT ASAP!! PLEASE HELP ME :)

Chemistry
2 answers:
AlladinOne [14]2 years ago
4 0

Answer : False, there will be two lithium and one oxygen atoms in a unit molecular structure of lithium oxide.

Explanation:

Electronic configuration of lithium is :

Li=1s^2s^1

In order to attain stable electronic configuration it will loose an electron and form positively charge cation.

Li^+=1s^22s^0

The electronic configuration of oxygen is:

O=1s^22s^22p^4

Oxygen being second most electronegative atom requires two electrons to attain noble gas configuration stability and form negatively charge ion with 2- charge.:

O^{2-}=1s^22s^22p^6

When two atom of lithium and oxygen comes together , one electron from each lithium atom get transferred to an oxygen atom which results in formation of lithium oxide.

2Li^++O^{2-}\rightarrow Li_2O

Molodets [167]2 years ago
3 0

HELLO :)

The answer would be false because the Lewis plot should contain 2 lithium atoms & 1 oxygen atom.

Since the lithium atom only contains 1 valence electron, then it wouldn't be enough to fill the valence shell of the oxygen atom because the oxygen only has 6 valence electrons in its valence shell. So it needs one more, that why it would need 2 lithium atoms.

hope this helps :P

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How would you prepare 3.5 L of a 0.9M solution of KCl?
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Calculate the mass of the solute <span>in the solution :

Molar mass KCl = </span><span>74.55 g/mol

m = Molarity * molar mass * volume

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m = 234.8325 g 

</span><span>To prepare 0.9 M KCl solution, weigh 234.8325 g of salt in an analytical balance, dissolve in a beaker, shortly after transfer with the help of a funnel of transfer to a volumetric flask of 100 cm</span>³<span> and complete with water up to the mark, then cover the balloon and finally shake the solution to mix

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Match each term with its definition. 1) reaction coordinate
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2 years ago
Determina el grado de pureza de un marmol (CaCO3), si al descomponerse 125 g del mismo se desprenden 20 litros de dióxido de car
jarptica [38.1K]

Answer:

67.8%

Explanation:

La reacción de descomposición del CaCO₃ es:

CaCO₃ → CO₂ + CaO

<em>Donde 1 mol de CaCO₃ al descomponerse produce 1 mol de CO₂ y 1 mol de CaO.</em>

Usando la ley general de los gases, las moles de dioxido de carbono son:

PV = nRT.

<em>Donde P es presión (1atm), V es volumen (20L), n son moles de gas, R es la constante de los gases (0.082atmL/molK) y T es temperatura absoluta (15 + 273.15 = 288.15K). </em>Reemplazando los valores en la ecuación:

PV / RT = n

1atmₓ20L / 0.082atmL/molKₓ288.15K = 0.846 moles

Como 1 mol de CO₂ es producido desde 1 mol de CaCO₃, las moles iniciales de CaCO₃ son 0.846moles.

La masa molar de CaCO₃ es 100.087g/mol. Así, la masa de 0.846moles de CaCO₃ es:

0.846moles ₓ (100.087g / mol) = <em>84.7g de CaCO₃</em>

Así, la pureza del marmol es:

(84.7g de CaCO₃ / 125g) ₓ 100<em> = </em>

<h3>67.8%</h3>
7 0
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