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neonofarm [45]
3 years ago
10

A teacher lifted a 10 N box and placed it down. Did she do any work? Explain your answer using math

Physics
1 answer:
Stells [14]3 years ago
8 0

Answer:

i think it is 45 kilograms not really sure?

Explanation:it might be wrong but i think it is right

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Suppose that a worker in Freedonia can produce either 6 units of corn or 2 units of wheat per year, and a worker in Sylvania can
Salsk061 [2.6K]

Answer:

a 30 units of corn and 30 units of wheat.

Explanation:

Initially freedonia has 5 workers producing 30 units of of corn (6 units per worker) and another 5 workers producing 10 units of wheat (2 units per worker)

With the trade agreed between the two countries Freedonia can have all of it's 10 workers producing corn, thereby producing 60 units of corn

30 of these are traded for 30 units of wheat therefore allowing the country to consume 30 units of each product.

8 0
3 years ago
The strength of the electric field at a certain distance from a point charge is represented by E. What is the strength of the el
Nana76 [90]

Answer:

E

Explanation:

Using Coulomb's law equation

Force of the charge = k qQ /d²

and E = F/ q

substitute for F

E = ( K Qq/ d² ) / q

q cancel q

E = KQ / d²

so twice  the distance of the from the point charge will lead to the E ( electric field ) decrease by a 4 = E/4. E is inversely proportional to d²

7 0
3 years ago
Timmy drove 2/5 of a journey at an average speed of 20 mph.
mixer [17]

Answer:

4hr

Explanation:

5 0
3 years ago
Read 2 more answers
d is at rest at the top of a 2 m high slope. The sled has a mass of 45 kg. The sled's potential energy is J?
Anna71 [15]
<span>D is at rest at the top of a 2 m high slope. The sled has a mass of 45 kg. The sled's potential energy is J?
</span>Answer: The sled's potential energy is 882 Joules
5 0
4 years ago
Read 2 more answers
You then measure Polly's internal temperature to be 13oC, which is quite a drop from the normal human body temperature of 37oC.
ankoles [38]

Answer:

The specific heat is 3.47222 J/kg°C.

Explanation:

Given that,

Temperature = 13°C

Temperature = 37°C

Mass = 60 Kg

Energy = 5000 J

We need to calculate the specific heat

Using formula of energy

Q= mc\Delta T

c =\dfrac{Q}{m\Delta T}

Put the value into the formula

c=\dfrac{5000}{60\times(37-13)}

c=3.47222\ J/kg^{\circ}C

Hence, The specific heat is 3.47222 J/kg°C.

5 0
3 years ago
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