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sattari [20]
3 years ago
11

Water can be heated above its boiling point without boiling. What is this process called? superheating vaporization melting cond

ensation supercooling
Chemistry
2 answers:
kirill [66]3 years ago
8 0
The answer is superheating
Alina [70]3 years ago
7 0
The answer to your question is superheating
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What is it called when energy is lost or removed?
enot [183]
I think it would be ionization
7 0
3 years ago
NEED ASAP!!!!
marin [14]

Answer:

A

D

E

and maybe C I'm not sure on that one.

Explanation:

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3 years ago
What is the volume of a 16.24 g sample of magnesium in cubic centimeters? Show a numerical setup and result for credit.
Virty [35]

Answer:

9.34 cm³

Explanation:

From the question given, we obtained the following data:

Mass of magnesium = 16.24 g

Volume of magnesium =.?

To obtain the volume of the magnesium sample, we simply apply the formula for calculating the density of samples. This is illustrated below:

Mass of magnesium = 16.24 g

Density of magnesium 1.738 g/cm³

Volume of magnesium =.?

Density = mass /volume

1.738 = 16.24/volume

Cross multiply

1.738 × volume = 16.24

Divide both side by 1.738

Volume of magnesium = 16.24/1.738

Volume of magnesium = 9.34 cm³

Therefore, the density of the magnesium sample is 9.34 cm³.

6 0
3 years ago
When a test instrument is calibrated, does its accuracy, precision, or reliability improve?
My name is Ann [436]

The answer is accuracy.

That is when a test instrument is calibrated, its accuracy is improved. That is the result comes more close to what it is.

The other factor will not be improved that is its reliability and precision remains the same.

So the answer is accuracy is improved when a test instrument is calibrated.

8 0
4 years ago
For the equilibrium reaction 2so2(g) + o2(g) 2so3(g), δhºrxn = –198 kj/mol. which one of these factors would cause the equilibri
Airida [17]
Let's rewrite the reaction for clarity:

 2 SO₂(g) + O₂(g) ⇆ 2 SO₃(g)            δhºrxn = –198 kj/mol

The equilibrium constant of a reaction is the ratio of the concentration its products to its reactants which are raised to their respective stoichiometric coefficients. For this reaction, the K would be

K = [SO₃]²/[SO₂]²[O₂]

To get a larger K, the products must be greater than the reactants. This means that the forward reaction must be favored to yield more of the product SO₃. There are different ways to do this: by manipulating the pressure, concentration or temperature.

For the concentration, you should add more amounts of the reactants. For the pressure, we should increase it. This is because the product side has only 2 moles of gas compared to 3 moles of gas in the reactants. So, it wall have more room for the product even at a higher pressure. Lastly, since the reaction is exothermic manifested by the negative sign of δhºrxn , the reaction would favor the forward reaction at high temperatures.
5 0
3 years ago
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