I think it would be ionization
Answer:
A
D
E
and maybe C I'm not sure on that one.
Explanation:
Answer:
9.34 cm³
Explanation:
From the question given, we obtained the following data:
Mass of magnesium = 16.24 g
Volume of magnesium =.?
To obtain the volume of the magnesium sample, we simply apply the formula for calculating the density of samples. This is illustrated below:
Mass of magnesium = 16.24 g
Density of magnesium 1.738 g/cm³
Volume of magnesium =.?
Density = mass /volume
1.738 = 16.24/volume
Cross multiply
1.738 × volume = 16.24
Divide both side by 1.738
Volume of magnesium = 16.24/1.738
Volume of magnesium = 9.34 cm³
Therefore, the density of the magnesium sample is 9.34 cm³.
The answer is accuracy.
That is when a test instrument is calibrated, its accuracy is improved. That is the result comes more close to what it is.
The other factor will not be improved that is its reliability and precision remains the same.
So the answer is accuracy is improved when a test instrument is calibrated.
Let's rewrite the reaction for clarity:
2 SO₂(g) + O₂(g) ⇆ 2 SO₃(g) δhºrxn = –198 kj/mol
The equilibrium constant of a reaction is the ratio of the concentration its products to its reactants which are raised to their respective stoichiometric coefficients. For this reaction, the K would be
K = [SO₃]²/[SO₂]²[O₂]
To get a larger K, the products must be greater than the reactants. This means that the forward reaction must be favored to yield more of the product SO₃. There are different ways to do this: by manipulating the pressure, concentration or temperature.
For the concentration, you should add more amounts of the reactants. For the pressure, we should increase it. This is because the product side has only 2 moles of gas compared to 3 moles of gas in the reactants. So, it wall have more room for the product even at a higher pressure. Lastly, since the reaction is exothermic manifested by the negative sign of δhºrxn , the reaction would favor the forward reaction at high temperatures.
