The distance covered by the plane in its accelerated motion is 750 m
Explanation:
The motion of the plane is a uniformly accelerated motion, so we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
t is the time
s is the displacement
For the plane in this problem,
is the initial velocity
v = 0 (the plane comes to a stop)
t = 30 s
Solving for s, we find the displacement of the plane, which corresponds to the distance covered:
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