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Vilka [71]
2 years ago
7

The gasoline in a car does 40,000 J of work on a car and generates a constant force of 20 N. How far did the car go?

Physics
1 answer:
AnnyKZ [126]2 years ago
7 0

L=F•d=>d=L/F=40,000/20=2,000 m

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Which of the following temparature is approximately equal to room temperature
Artist 52 [7]

Hello there! :)

\huge\boxed{\text{C. 293K}}

Room temperature is approximately 20°C.

We can automatically eliminate choices B and D since they are not equal to 20°C.

Since some choices use the Kelvin scale, we can convert from Celsius to Kelvin using a simple formula:

K = C° + 273

Find room temperature in degrees <u>Kelvin</u>:

K = 20° + 273

K = 293°

Thus, the correct choice would be <u>C. 293K.</u>

6 0
3 years ago
Determine the magnitude and direction of the force on an electron traveling 3.58 E 6 m/s horizontally to the west in a verticall
olya-2409 [2.1K]

Answer:banana

Explanation:

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4 0
2 years ago
The three different states of matter are liquid, solid, and gas. A solid is something you can hold in your fingers, while a liqu
nika2105 [10]

The answer is C. that liquids and gases both take the shape of their container.  

Think of it this way, if you take an ice cube and put it in your glass, it will stay in its shape and stay that way until it melts.  But if you put liquid or a gas into a glass, it will take the shape of the glass that it is put into.  

3 0
3 years ago
Read 2 more answers
How much force should a mother exert to lift a 5.0-kg child​
andrew11 [14]

Answer:

F = 49N

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8 0
3 years ago
You will now examine the relationship between the number of field lines through a surface and the tangle betwcen A and E) angle
nikitadnepr [17]

Answer:

a. cosθ b. E.A

Explanation:

a.The electric flux, Φ passing through a given area is directly proportional to the number of electric field , E, the area it passes through A and the cosine of the angle between E and A. So, if we have a surface, S of surface area A and an area vector dA normal to the surface S and electric field lines of field strength E passing through it, the component of the electric field in the direction of the area vector produces the electric flux through the area. If θ the angle between the electric field E and the area vector dA is zero ,that is θ = 0, the flux through the area is maximum. If  θ = 90 (perpendicular) the flux is zero. If θ = 180 the flux is negative. Also, as A or E increase or decrease, the electric flux increases or decreases respectively. From our trigonometric functions, we know that 0 ≤ cos θ ≤ 1 for  90 ≤ θ ≤ 0 and -1 ≤ cos θ ≤ 0 for 180 ≤ θ ≤ 90. Since these satisfy the limiting conditions for the values of our electric flux, then cos θ is the required trigonometric function. In the attachment, there is a graph which shows the relationship between electric flux and the angle between the electric field lines and the area. It is a cosine function  

b. From above, we have established that our electric flux, Ф = EAcosθ. Since this is the expression for the dot product of two vectors E and A where E is the number of electric field lines passing through the surface and A is the area of the surface and θ the angle between them, we write the electric flux as Ф = E.A  

4 0
3 years ago
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