Explanation:
According to the psychrometric chart at dry bulb temperature of
and RH 70%, the absolute humidity = 0.011 kg/kg dry air
Formula to calculate humid volume is as follows.
dry air = 
= 
= 
= 0.847
dry air
Hence, humid volume of air is 0.847
dry air.
Specific enthalpy of dry air = specific heat capacity of dry air × dry bulb temperature
=
= 21.126 kJ/kg dry air
Hence, the specific enthalpy of the air is 21.126 kJ/kg dry air.
As per the psychrometric chart at given conditions wet bulb temperature = 17.5 
As per the psychrometric chart at given conditions dew point temperature = 15.5 
Answer:
-800 kJ/mol
Explanation:
To solve the problem, we have to express the enthalpy of combustion (ΔHc) in kJ per mole (kJ/mol).
First, we have to calculate the moles of methane (CH₄) there are in 2.50 g of substance. For this, we divide the mass into the molecular weight Mw) of CH₄:
Mw(CH₄) = 12 g/mol C + (1 g/mol H x 4) = 16 g/mol
moles CH₄ = mass CH₄/Mw(CH₄)= 2.50 g/(16 g/mol) = 0.15625 mol CH₄
Now, we divide the heat released into the moles of CH₄ to obtain the enthalpy per mole of CH₄:
ΔHc = heat/mol CH₄ = 125 kJ/(0.15625 mol) = 800 kJ/mol
Therefore, the enthalpy of combustion of methane is -800 kJ/mol (the minus sign indicated that the heat is released).
Your answer would be an Arrhenius base
Hope this helps