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3 years ago

how would you write equation to show how buffers H2CO3 and NaHCO3 behave when (a) HCl is added and (b) NaOH is added.

1 answer:

8 0

H2CO3 <---> H+ + HCO3-
NaHCO3 <---> Na+ + HCO3-

When acid is added in the buffer, the excess H+ of that acid reacts with HCO3- to form H2CO3, and due to this NaHCO3 dissociates into HCO3- to attain the equilibrium. and hence there is no net effect of H+ due to pH remain almost constant. when a base is added to the buffer, the OH- ion of base react eith H+ ion present in buffer, then to attain equilibrium of H+ ion, the H2CO3 dissociates to produce H+ ion, but now there is the excess of HCO3- due to which Na+ ion react with them to attain equilibrium of HCO3-. hence there is again no net change in H+ ion due to which pH remain constant.....

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Explanation:

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2 years ago

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Explanation:

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3 years ago

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nata0808 [166]

Increasing pH will increase the solubility of the Hg2(CN)2 by shifting equilibrium to right side.

What is the meaning of OH in chemistry?

The chemical group, ion, or radical OH that consists of one atom of hydrogen and one of oxygen and is neutral or negatively charged.

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adding OH- to the mercury(l) cyanide will cause the formation of the solid HgO.

therefore increasing pH will increase the solubility of the Hg2(CN)2 by shifting equilibrium to right side.

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1 year ago

Which pair of reactants will undergo aldol condensation to produce methylvinyl ketone?

xenn [34]

When formaldehyde and acetone then react with each other( aldol condensation) then it will be formed methyl vinyl ketone.

In organic chemistry, an aldol condensation would be a condensation reaction in which an enol and enolate ion combines with a carbonyl chemical to produce a -hydroxy aldehyde or -hydroxy ketone, that is then dehydrated to produce a conjugated enone.

In aldol condensation, when formaldehyde and acetone then react with each other then it will be formed methyl vinyl ketone.

It can be written as

$CH_{2} O + CH_{3} COCH_{3}$ → $HOCH_{2} -CH_{2} -CO-CH_{3}$

When it will be heated then it gives methyl vinyl ketones.

$HOCH_{2} -CH_{2} -CO-CH_{3}$ → $CH_{2} =CH-CO-CH_{3}$

So, the pair of reactants will be formaldehyde and acetone

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