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BabaBlast [244]
3 years ago
9

how would you write equation to show how buffers H2CO3 and NaHCO3 behave when (a) HCl is added and (b) NaOH is added.

Chemistry
1 answer:
Vlad1618 [11]3 years ago
8 0
<span>H2CO3 <---> H+ + HCO3-
NaHCO3 <---> Na+ + HCO3-

When acid is added in the buffer, the excess H+ of that acid reacts with HCO3- to form H2CO3, and due to this NaHCO3 dissociates into HCO3- to attain the equilibrium. and hence there is no net effect of H+ due to pH remain almost constant. when a base is added to the buffer, the OH- ion of base react eith H+ ion present in buffer, then to attain equilibrium of H+ ion, the H2CO3 dissociates to produce H+ ion, but now there is the excess of HCO3- due to which Na+ ion react with them to attain equilibrium of HCO3-. hence there is again no net change in H+ ion due to which pH remain constant.....</span>
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<u>Answer:</u> The time required for the conversion of benzoyl chloride to benzoic acid is 390 seconds.

<u>Explanation:</u>

The expression for the rate law of first order kinetics is given as:

\ln \frac{N}{N_o}=e^{-kt}      ......(1)

where,

N_o = initial mass of isotope = 100 g

N = mass of the parent isotope left after the time = 100 - 25 = 75 g

t = time taken = 26 s

k = rate constant = ?

Putting values in above equation, we get:

\ln \frac{75}{100}=e^{-k\times 26}\\\\k=0.011065s^{-1}

Now, we need to find the time when 99 % of the reaction is complete. Using equation 1 again, we get:

N_o = initial mass of isotope = 100 g

N = mass of the parent isotope left after the time = 100 - 99 = 1 g

t = time taken = ? s

k = rate constant = 0.011065s^{-1}

Putting values in above equation, we get:

\ln \frac{1}{100}=e^{-0.011065\times t}\\\\t=416s

Time required for the conversion of benzoyl chloride to benzoic acid = 416 - 26 = 390 s

8 0
2 years ago
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