A motorcycle has a mass of 350kg. A force of 1295N is applied to the cycle what is the motorcycles acceleration

1 answer:

Maru [420]3 years ago

4 0

Answer: $3.7 m/s^2$

Explanation:

The acceleration of the motorcycle is given by Newton's second law:

$a=\frac{F}{m}$

where

F = 1295 N is the force applied to the motorcycle

m = 350 kg is the mass of the motorbike

a is the acceleration

By substituting the numbers into the formula, we find

$a=\frac{F}{m}=\frac{1295 N}{350 kg}=3.7 m/s^2$

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GalinKa [24]

The magnitude of the force that the beam exerts on the hi.nge will be,261.12N.

To find the answer, we need to know about the tension.

<h3>How to find the magnitude of the force that the beam exerts on the hi.nge?</h3>

Let's draw the free body diagram of the system using the given data.
From the diagram, we have to find the magnitude of the force that the beam exerts on the hi.nge.
For that, it is given that the horizontal component of force is equal to the 86.62N, which is same as that of the horizontal component of normal reaction that exerts by the beam on the hi.nge.

$N_x=86.62N$

We have to find the vertical component of normal reaction that exerts by the beam on the hi.nge. For this, we have to equate the total force in the vertical direction.

$N_y=F_V=mg-Tsin59\\$