All categories

3 years ago

A motorcycle has a mass of 350kg. A force of 1295N is applied to the cycle what is the motorcycles acceleration

Physics

1 answer:

Maru [420]3 years ago

4 0

Answer: $3.7 m/s^2$

Explanation:

The acceleration of the motorcycle is given by Newton's second law:

$a=\frac{F}{m}$

where

F = 1295 N is the force applied to the motorcycle

m = 350 kg is the mass of the motorbike

a is the acceleration

By substituting the numbers into the formula, we find

$a=\frac{F}{m}=\frac{1295 N}{350 kg}=3.7 m/s^2$

You might be interested in

You want to raise the temperature of 22kg of water from 60°C to 95°C. If electricity costs $0.08/kWh, how much would it cost you

Sladkaya [172]

Answer:

dgtgh

Explanation:

dgdfhdhfffff thdhfghjfj e

3 0

3 years ago

10. A hockey puck with mass 0.3 kg is sliding along ice that can be considered frictionless. The puck’s velocity is 20 m/s when

SVEN [57.7K]

Answer:

$d = \frac{v^2_i}{2a}= \frac{(20m/s)^2}{2* 3.43 m/s^2}=58.309m$

Explanation:

For this case we can use the second law of Newton given by:

$\sum F = ma$

The friction force on this case is defined as :

$F_f = \mu_k N = \mu_k mg$

Where N represent the normal force, $\mu_k$ the kinetic friction coeffient and a the acceleration.

For this case we can assume that the only force is the friction force and we have:

$F_f = ma$

Replacing the friction force we got:

$\mu_k mg = ma$

We can cancel the mass and we have:

$a = \mu_k g = 0.35 *9.8 \frac{m}{s^2}= 3.43 \frac{m}{s^2}$

And now we can use the following kinematic formula in order to find the distance travelled:

$v^2_f = v^2_i - 2ad$

Assuming the final velocity is 0 we can find the distance like this:

$d = \frac{v^2_i}{2a}= \frac{(20m/s)^2}{2* 3.43 m/s^2}=58.309m$

5 0

3 years ago

A convection cell is BEST described as ___.

Helga [31]

D, a loop of moving air

6 0

3 years ago

Which of the following is an example of a chemical property? Density Solubility Flammability Magnetism

choli [55]

The answer should be flammability

8 0

4 years ago

Equations to use: v= λ ∙ f v=d/t

Margarita [4]

b. 460.8 m/s

Explanation:

The relationship between the speed of the wave along the string, the length of the string and the frequency of the note is

$f=\frac{v}{2L}$

where v is the speed of the wave, L is the length of the string and f is the frequency. Re-arranging the equation and substituting the data of the problem (L=0.90 m and f=256 Hz), we can find v:

$v=2Lf=2(0.90 m)(256 Hz)=460.8 m/s$

c. 18,000 m

Explanation:

The relationship between speed of the wave, distance travelled and time taken is

$v=\frac{d}{t}$

where

v = 6,000 m/s is the speed of the wave

d = ? is the distance travelled

t = 3 s is the time taken

Re-arranging the formula and substituting the numbers into it, we find:

$d=vt=(6,000 m/s)(3 s)=18,000 m$

3 0

3 years ago