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likoan [24]
2 years ago
7

A 2300-kg car slows down at a rate of 3.0 m/s2 when approaching a stop sign. What is the magnitude of the net force causing it t

o slow down?
Physics
1 answer:
weeeeeb [17]2 years ago
4 0

The magnitude of the net force causing the 2300kg car to slow down is 6900N

HOW TO CALCULATE FORCE:

  • The net force applied on a moving object can be calculated by multiplying the mass of the object by its acceleration. That is;

  • Force (N) = mass (kg) × acceleration (m/s²)

  • According to this question, a 2300-kg car slows down at a rate of 3.0 m/s2 when approaching a stop sign. The net force causing the car to stop can be calculated as follows:

F = 2300kg × 3m/s²

F = 6900N

  • Therefore, the magnitude of the net force causing the 2300kg car to slow down is 6900N.

Learn more at: brainly.com/question/18109210?referrer=searchResults

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What is the resistance of al lamp that allows a current of 10 amps with 120 volts
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V=ir
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5 0
2 years ago
Quentin is playing baseball and is batting. He swings and hits the ball sending it flying to the outfield. Which is greater- the
Bess [88]

Answer:

The force of the ball on the bat is same as the force of the bat on the ball.  

Explanation:

A bat hits the ball and the ball moves to the out filed.

According to the Newton's third law, for every action there is an equal and opposite reaction.

The action and the reaction forces acts on the two different bodies but the magnitude of the force is same.  

As the ball is hitted by the bat, the bat exerts the force on the ball and the same force is exerted on the bat by the ball according to the Newton's third law.

So, the force of the ball on the bat is same as the force of the bat on the ball but the direction of force is opposite.  

5 0
3 years ago
THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THANKS!!!
poizon [28]

Answer:

391.67Hz

Explanation:

The fundamental frequency formula in string is expressed as;

Fo = V/2L

V is the velocity of the wave = 329m/s

L is the length of the string = 42cm = 0.42m

Substitute

Fo = 329/2(0.42)

Fo = 329/0.84

Fo = 391.67Hertz

Hence the  fundamental frequency of a mandolin string is 391.67Hz

4 0
3 years ago
Part 1: A rope has one end tied to a vertical support. You hold the other end so that the rope is horizontal. If you move the en
Blizzard [7]

Answer:

c. 2 m/s

Explanation:

The speed of a wave is given by:

v=f \lambda

where

v is the speed of the wave

f is the frequency

\lambda is the wavelength

For the wave in this problem, we have

f = 4 Hz is the frequency

\lambda = 0.5 m is the wavelength

So, the speed of the wave is

v=(4 Hz)(0.5 m)=2 m/s

5 0
3 years ago
g The bottom end of a long vertical tube filled with liquid is opened in a basin exposed to air having pressure 100.8 kilo-Pasca
Masja [62]

Answer:

979.6 kg/m³

Explanation:

We know pressure P = hρg where h = height of liquid = 10.5 m, ρ = density of liquid and g = acceleration due to gravity = 9.8 m/s²

So, density ρ = P/hg

Since P = 100.8 kPa = 100.8 × 10³ Pa

substituting the values of the variables into the equation for ρ, we have

ρ = P/hg

= 100.8 × 10³ Pa ÷ (10.5 m × 9.8 m/s²)

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= 0.9796 × 10³ kg/m³

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So, the density of the liquid is 979.6 kg/m³

3 0
3 years ago
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