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likoan [24]
2 years ago
7

A 2300-kg car slows down at a rate of 3.0 m/s2 when approaching a stop sign. What is the magnitude of the net force causing it t

o slow down?
Physics
1 answer:
weeeeeb [17]2 years ago
4 0

The magnitude of the net force causing the 2300kg car to slow down is 6900N

HOW TO CALCULATE FORCE:

  • The net force applied on a moving object can be calculated by multiplying the mass of the object by its acceleration. That is;

  • Force (N) = mass (kg) × acceleration (m/s²)

  • According to this question, a 2300-kg car slows down at a rate of 3.0 m/s2 when approaching a stop sign. The net force causing the car to stop can be calculated as follows:

F = 2300kg × 3m/s²

F = 6900N

  • Therefore, the magnitude of the net force causing the 2300kg car to slow down is 6900N.

Learn more at: brainly.com/question/18109210?referrer=searchResults

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Hoochie [10]

Answer:

26b) 66.7%

27) 500 N

Explanation:

26.a) In a two pulley system, the load is attached to one of the pulleys.  The other pulley is attached to a fixed surface, as well as one end of the rope.  The other end of the rope goes around moving pulley, then around the fixed pulley.

26.b) Mechanical advantage is the ratio between the forces:

MA = load force / effort force

Efficiency is the ratio between the work:

e = work done on load / work done by effort

Work is force times distance.

e = (F load × d load) / (F effort × d effort)

Rearranging:

e = (F load / F effort) × (d load / d effort)

e = MA × (d load / d effort)

In a two pulley system, the load moves half the distance of the effort.  So the efficiency is:

e = (4/3) × (1/2)

e = 2/3

e = 66.7%

27) In a three pulley system, the load moves a third of the distance of the effort.

e = (F load / F effort) × (d load / d effort)

0.40 = (600 N / F) × (1/3)

F = 500 N

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3 years ago
What is the direction of acceleration due to gravity​
Paul [167]

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Negative, because the speed is decreasing.

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NEED HELP NOW WILL GIVE BRAINLIEST
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pls mark me brainliest its the right answer

6 0
2 years ago
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Formula: KE = 1/2 my?
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Answer:

22400 Joules

Explanation:

Apply the formula:

KE = 1/2 . 40 . 1120

KE = 20 . 1120

KE = 22400 Joules

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The correct answer is Mechanics
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