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Elan Coil [88]
3 years ago
12

Light will not pass through a pair of polaroids when their axes are

Physics
1 answer:
Advocard [28]3 years ago
8 0

Answer:

perpendicular

Explanation:

Polaroids are the material that is used to polarize the ray of light. Polaroid consists of microcrystals of herapathite.

When unpolarized light is passed through the Polaroid then ray appears to be of half the intensity and vibration of the ray in the single plane so, the emerged light is known as polarized light

Polaroids are used in the glasses to protect the eye from unwanted rays.

When Light does not pass through a pair of Polaroids then the axis of Polaroids will be perpendicular to the axis of ray.

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How is the density of a substance calculated?
den301095 [7]
1).  Take a sample of the substance.  The sample should be the largest
possible that will allow it to be be easily handled and the following steps
to be performed with it. 
(The density doesn't depend on the size of the sample, and every sample
of the same substance has the same density.  But using a larger sample
can improve the accuracy of the measurements you make, and therefore
improve the accuracy of the density you derive for the substance.)

2). Ask or measure the mass of the sample.

3). Ask or measure the volume of the sample.

4). Divide the mass by the volume. Their quotient is the density
of the substance.
3 0
3 years ago
An electromagnet needs a magnetic metal core. To produce a magnetic field, what else is required?
a_sh-v [17]

Answer:

B

Explanation:

A solenoid is the wraps of conducting wire wrapped around the metal core .

5 0
2 years ago
A constant magnetic field passes through a single rectangular loop whose dimensions are 0.35 m × 0.55 m. The magnetic field has
Pani-rosa [81]

Answer:

Part a)

EMF = 0.38 V

Part b)

\frac{dA}{dt} = 0.43 m^2/s

Explanation:

Part a)

Initial value of magnetic flux is given as

\phi_1 = BAcos\theta

\phi_1 = (2.1)(0.35 \times 0.55) cos65

so we have

\phi_1 = 0.17 Wb

Final flux through the loop is given as

\phi_2 = 0

now EMF is given as

EMF = \frac{\phi_1 - \phi_2}{\Delta t}

EMF = \frac{0.17 - 0}{0.45}

EMF = 0.38 V

Part b)

If magnetic field is constant while Area is changing

So EMF is given as

E = Bcos65 \times \frac{dA}{dt}

0.38 = 2.1 cos65(\frac{dA}{dt})

\frac{dA}{dt} = 0.43 m^2/s

5 0
3 years ago
A hollow cylinder with an inner radius of 4.0 mm and an outer radius of 30 mm conducts a 3.0-Acurrent flowing parallel to the ax
Kryger [21]

Answer:

the magnitude of the magnetic field is 0.45 mT

Explanation:

Knowing the formula

B = \frac{m0* (i - i')}{2* Pi* r}

i = 3A    i' = 0A

B = \frac{4*3.1416e^{-7} * (3-0) }{2*3.1416*0.012}

B = 0.45 mT

8 0
3 years ago
What is the magnitude of the centripetal force that must be applied in order for a 2kg ball on a 2.0 m string to spin with unifo
NeTakaya

The ball needs to accelerate with a magnitude <em>a</em> (pointed towards the center of the circle) of

<em>a</em> = (5.0 m/s)² / (2.0 m) = 12.5 m/s²

Then the required tension <em>F</em> in the string would need to be

<em>F</em> = (2 kg) (12.5 m/s²) = 25 N

6 0
3 years ago
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