A ball is dropped off the top of a 35 meter tall building. How fast will it be going when it reaches
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Answer:
<h3>30.66m</h3>Explanation:
Using the equation of motion formula where;
S is the height to which the ball rises
u is the initial velocity of the ball = 0m/s
a is the acceleration due to gravity = 9.81m/s²
t is the time taken by the ball in air = 5.0s
Note that the time to rise to the peak is one-half the total hang-time = 5.0/2 = 2.5s
Substituting the given parameters into the formula above to get S:
This means that the ball rises 30.66m before it reaches its peak.