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Korolek [52]
3 years ago
6

calcium and strontium are close to one another on thw oeriodic table. what do you know about their ionization energies ,their el

ectron configurations and their charasteristics based on their position in the periodic table?

Chemistry
1 answer:
Firdavs [7]3 years ago
4 0

Both Ca and Sr are in Group 2 of the Periodic Table, with Sr below Ca (see image)..

<em>Ionization energies </em>

They are both metals, so they have relatively <em>low ionization energies</em>.

Sr is below Ca in the Group, so Sr has the lower ionization energy.

<em>Electron configurations </em>

Their electron configurations both end in <em>ns²</em>.

For example, the electron configuration of Ca is [Kr]<em>4s²</em> and that of Sr is [Kr]<em>5s²</em>.

<em>Physical chsrscteristics: </em>

  • metallic lustre
  • malleable
  • ductile
  • good conductors of heat and electricity

<em>Chemical characteristics</em>

Both metals react with

• <em>Hydrogen</em> to form hydrides: M + H₂ ⟶ MH₂

• <em>Oxygen</em> to form oxides: 2M + O₂ ⟶ 2MO

• <em>Nitrogen</em> to form nitrides: 3M + N₂ ⟶ M₃N₂

• <em>Halogens</em> to form halides: M + X₂ ⟶ MX₂

• <em>Water</em> to displace hydrogen: M + 2H₂O ⟶ M(OH)₂ + H₂

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Calculate the concentration of a solution that has 6.7 moles in a volume of 0.6 liters.
Yuri [45]

Answer:

11.2 M

Explanation:

Given data:

Number of moles = 6.7 mol

Volume of solution = 0.6 L

Concentration /Molarity = ?

Solution:

Molarity:

It is number of moles of solute in to per kg or litters of solution. It can be calculated by the following formula.

Molarity = number of moles / Volume in L

Now we will put the values in formula.

Molarity = 6.7 mol / 0.6 L

Molarity = 11.2 mol/L

Molarity = 11.2 M

6 0
3 years ago
A 12400. mL container holds a sample of argon gas at 35.00C and
xz_007 [3.2K]

Answer:

0.574moles

Explanation:

Using the general gas equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (Litres)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (Kelvin)

According to the information provided in the question;

- Volume (V) = 12400mL = 12400/1000 = 12.4L

- Pressure (P) = 890mmHg = 890/760 = 1.17atm

- Temperature (T) = 35°C = 35 + 273 = 308K

Hence, using PV = nRT

n = PV/RT

n = 1.17 × 12.4 ÷ 0.0821 × 308

n = 14.508 ÷ 25.287

n = 0.574moles

Therefore, the number of moles of argon gas in the cylinder is 0.574moles

7 0
3 years ago
Is gunpowder a homogenous mixture or a heterogenous mixture? Explain why.
inysia [295]

Gunpowder is a heterogenous mixture,

Reason : the composiotion of the mixture is not uniform throughout, the mixture can be separated by a suitable method , and finally , it composes of charcoal, sulfur and potassium nitrate which is not homogeneous mixture.

4 0
1 year ago
At the Henry's Law constant for carbon dioxide gas in water is . Calculate the mass in grams of gas that can be dissolved in of
Dvinal [7]

The question is incomplete, here is the complete question:

At 25°C Henry's Law constant for carbon dioxide gas in water is 0.031 M/atm . Calculate the mass in grams of gas that can be dissolved in 425. mL of water at 25°C and at a partial pressure of 2.92 atm. Round your answer to 2 significant digits.

<u>Answer:</u> The mass of carbon dioxide that can be dissolved is 1.7 grams

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{CO_2}=K_H\times p_{CO_2}

where,

K_H = Henry's constant = 0.031M/atm

C_{CO_2} = molar solubility of carbon dioxide gas

p_{CO_2} = partial pressure of carbon dioxide gas = 2.92 atm

Putting values in above equation, we get:

C_{CO_2}=0.031M/atm\times 2.92 atm\\\\C_{CO_2}=0.0905M

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of carbon dioxide = ? g

Molar mass of carbon dioxide = 44 g/mol

Molarity of solution = 0.0905mol/L

Volume of solution = 425 mL

Putting values in above equation, we get:

0.0905mol/L=\frac{\text{Mass of carbon dioxide}\times 1000}{44g/mol\times 425}\\\\\text{Mass of solute}=\frac{44\times 425\times 0.0905}{1000}=1.7g

Hence, the mass of carbon dioxide that can be dissolved is 1.7 grams

8 0
3 years ago
Rolls of foil are 300mm wide and 2.020mm thick. (The density of foil is 2.7 g/cm^3). What maximum length of foil can be made fro
horrorfan [7]

Answer:  8556 mm, or 855.6 cm (8560 mm to 3 sig figs)

Explanation:  Convert mm to cm by dividing by 10 (1cm/10mm)

Find the area of the foil face in cm^2 (30cm*0.2020cm) = 0.606 cm^2

Calculate the volume occupied by 1.40 kg of foil in cm^3.  1.40kg = 1400g

1.400g/(2.7 g/cm^3) = 518.5 cm^3 for 1.40 kg Au

   Volume = Area (of the face) * Length  

We want Length:

Length = Volume/Area

L = (518.5 cm^3/0.606 cm^2)

L = 855.6 cm (8556 mm)  Round to 3 sig figs (856 cm and 8560 mm)

5 0
2 years ago
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