<h3>
Answer:</h3>
83.33 seconds.
<h3>
Explanation:</h3>
<u>We are given;</u>
- Take off velocity as 300 km/hr
- Acceleration as 1 m/s²
We are required to calculate the take off time of the airplane.
<h3>Step 1: Convert velocity from km/hr to m/s </h3>
We are going to use the conversion factor.
The conversion factor is 3.6 km/hr per m/s
Therefore;
Velocity = 300 km/hr ÷ 3.6 km/hr per m/s
= 83.33 m/s
<h3>Step 2: Calculate the take off time</h3>
We know that;
v = u + at
where, u is the initial velocity, v the final velocity, a the acceleration and t is time.
But, initial velocity is Zero
Therefore;
83.33 m/s = 1 m/s² × t
Thus;
time = 83.33 m/s ÷ 1 m/s²
= 83.33 seconds
Therefore, the take off time is 83.33 seconds.
Answer:
X20 Can it is answer for this question
Answer:
Q = 63.75J
Explanation:
Mass = 2.5g
Initial temperature (T1) = 25°C
Final temperature (T2) = 50°C
Specific heat capacity of Mg = 1.020J/g°C
Heat energy = ?
Heat Energy (Q) = mc∇T
Q = heat energy
M = mass of substance
C = specific heat capacity of substance
∇T = change in temperature = T2 - T1
Q = mc∇T
Q = mc(T2 - T1)
Q = 2.5 × 1.020 × (50 - 25)
Q = 2.55 × 25
Q = 63.75J
The heat energy required to raise magnesium metal from 25°C to 50°C is 63.75J
The addition of hydrogen carbonate to bromothymol blue turns the solution blue. Thus, option B is correct.
The balanced equation for the dissociation of bromothymol blue is:

The color of dissociated form is yellow and undissociated form is blue.
<h3>What is the final color of solution?</h3>
The addition of hydrogen carbonate results in the dissociated ions as:

The dissociation results in the increased hydrogen ion concentration. The undissociated form in the reaction mixture increases.
Thus, the color of the solution will turn blue. Hence, option B is correct.
Learn more about bromothymol blue, here:
brainly.com/question/24319054
Answer:
Five peaks
Explanation:
GaAs would show two peaks:
Ga-69 + As-75 = 144
Ga-71 + As-75 = 146
Their intensities are in the ratio 60 : 40 = 100:67.
Ga₂S₂ would show three peaks:
Ga-69 + Ga-69 + 2As-75 = (Ga-69)₂(As-75)₂ = 288
Ga-69 + Ga-71 + 2As-75 = (Ga-69)(Ga-71(As-75)₂ = 290
Ga-71 + Ga-71 + 2As-75 = (Ga-71)₂(As-75)₂ = 292
Their relative intensities are in the ratio
(60 + 40)² = 60² : 2×60×40 : 40² = 3600 : 4800 : 1600 = 75 : 100 : 33
A spectrum of a mixture of GaAs and Ga₂As₂ would show five peaks:
Two at m/e 144 and 146 with intensity ratios 100: 67 and
Three at m/e 288, 290, and 292 with intensity ratios 75:100 :33.
We cannot predict the absolute sizes of the peaks because we do not know the relative amounts of GaAs and GaAs₂.