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3 years ago

If f(x) =3x+5 and g(x) =x-1, then f[g(0) =?

Mathematics

1 answer:

Kisachek [45]3 years ago

8 0

G(0)= 0-1= -1

f(-1)= 3(-1)+5= -3+5= 2

the answer to the question is 2

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What is the value for m and n?

Inga [223]

Answer:

M = 8 N = 10

Step-by-step explanation:

Multiplying exponents adds the exponent, meaning that inside of the brackets, it is a^4 * b^5. Multiply the exponents by two because you are squaring the entire equation. Therefore, m=8 and n=10

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2 years ago

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3 years ago

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Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4

gtnhenbr [62]

Answer:

Simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

$(6^{-2})(3^{-3})(3*6)^4$

Applying exponent rule: $a^{-m}=\frac{1}{a^m}$

$=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\$

Factors of $18=2\times 3\times 3=2\times3^2$

Factors of $6=2\times 3$

Replacing terms with factors

$=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\$

Using exponent rule: $(a^m)^n=a^{m\times n}$

$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

Using exponent rule: $a^m.a^n=a^{m+n}$

$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

Now using exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

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2 years ago

What is the difference of 15 and 7?<br> O<br> 3<br> Sondrit<br> Not

viva [34]

Answer:

Step-by-step explanation:

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2 years ago

Find the value of f(g(-2))

PSYCHO15rus [73]

Answer:

The correct ans is 3.

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=-4 + 5 = 1

f(g(-2)) = 4 - (1)^2

= 4 - 1

Step-by-step explanation:

4 0

2 years ago