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Tju [1.3M]
3 years ago
6

Supposing you were in space..in a weightless environment, would it require a force to set an object in motion? Explain..

Physics
1 answer:
Dvinal [7]3 years ago
8 0

Answer:

Yes, a force is require to set an object in motion.

Explanation:

  • In space, even if you feel weightless, you are subject to motion. If you are orbiting the Earth, you are under the constant influence of Earth having a free-fall acceleration equal to the centripetal acceleration.
  • To disturb this orbital motion, an external force is required.
  • According to Newton's laws of motion, a force is required to change the state of the rest of a body or to change the velocity or direction if it is moving with uniform velocity along a straight line.
  • Whenever there is a change in velocity or direction of a body there is a force acting on it.
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What are five of the most important things you learned in physics? ASAP
scoundrel [369]

Answer:

The definitions of mass, energy, time and space as used in Physics are circular

The Conservation of Mass and Energy

The definition of zero is not sufficiently defined in Physics

Newton’s Laws of Motion are related by Calculus

Knowing the terms of Physics is most important.

Please mark as brainliest

7 0
3 years ago
Which example shows an endothermic reaction?
Nata [24]

Answer:

reactants --> products + thermal energy

Explanation:

Heat is absorbed in endothermic reaction.

6 0
3 years ago
An object with a mass of 5.0 kg is accelerating toward the surface of Earth at a rate of 9.8 m/s^2
vlabodo [156]
The answer is A. Force is equal to mass x acceleration. The acceleration due to gravity is a constant so multiplying the mass by 2 would double the force.
4 0
4 years ago
An airplane is flying in a horizontal circle at a speed of 480 km/h. If its wings are tilted 40° to the horizontal, what is the
guajiro [1.7K]

Answer:

r = 2161.9 m

Explanation:

Aerodynamic lift(L) is perpendicular to the wing, which is tilted 40 degrees to the horizontal.

Since the plane is moving in a horizontal circle, the vertical component of the lift must cancel the weight W of the airplane, but the horizontal component is the centripetal force that keeps it in a circle.

L is perpendicular to wing at angle θ with respect to horizontal

Thus,

Vertical component of lift is:

L cosθ = W = mg

Thus, m = L cosθ / g - - - - (eq1)

Horizontal component of lift is:

L sinθ = centripetal force = mv² / r - - - - (eq2)

Combining equations 1 and 2,we have;

L sinθ = (L cosθ / g)(v² / r)

L cancels out on both sides to give;

tanθ = v²/ rg

r = v² / (g tanθ)

We are given;

velocity; v = 480 km/hr = 480 x 10/36 = 133.33 m/s

r = 133.33²/[(9.8) tan(40)] = 2161.9 m

3 0
3 years ago
A 400 gram sample of alcohol at 10o C [Ca=2.64 J/g*oC] is mixed with 400 grams of warm water [Cw=4.186 J/g*Co] at 88o C. Assume
alukav5142 [94]
The heat lost by the water will be equivalent to the energy gained by the alcohol. Thus:
maCaΔT = -mwCwΔT
400 x 2.64 x (T - 10) = 400 x 4.186 x (88 - T)
T = 57.8 °C
8 0
3 years ago
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