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3 years ago

6

Supposing you were in space..in a weightless environment, would it require a force to set an object in motion? Explain..

1 answer:

Dvinal [7]3 years ago

8 0

Answer:

Yes, a force is require to set an object in motion.

Explanation:

In space, even if you feel weightless, you are subject to motion. If you are orbiting the Earth, you are under the constant influence of Earth having a free-fall acceleration equal to the centripetal acceleration.
To disturb this orbital motion, an external force is required.
According to Newton's laws of motion, a force is required to change the state of the rest of a body or to change the velocity or direction if it is moving with uniform velocity along a straight line.
Whenever there is a change in velocity or direction of a body there is a force acting on it.

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Object A moves with a constant velocity of -10 m/s and object B moves with a constant velocity of 5 m/s. Which object has the la

KonstantinChe [14]

Object A has the larger speed because speed is not a vector quantity, it is scalar. This means that directionality, or in this case the sign of the velocity, doesn’t matter.
Speed = |velocity|
Object a speed =|-10|=10 m/s
Object b speed =|5|=5 m/s

Object a is the answer.

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3 years ago

You are working in a biology lab and learning to use a new ultracentrifuge for blood tests. The specifications for the centrifug

Sloan [31]

Answer:

Yes, correct

Explanation:

velocity, v = 470 m/s

radius, r = 0.15 m

The radial acceleration is the centripetal acceleration which always acts towards the centre of the circular centrifuge.

The formula for the centripetal acceleration is given by

$a =\frac{v^{2}}{r}$

$a =\frac{470^{2}}{0.15}$

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a = 150272.1 g

According to the question, we can get the acceleration as mentioned. So the claim is correct.

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3 years ago

Read 2 more answers

A car starting from rest accelerates at a constant 2.0 m/s2 for 10 s. It then travels with constant speed it has achieved for an

Anon25 [30]

Answer:

The total distance will be 400 m.

Explanation:

For portion AB:

Acceleration = 2 $m/s^2$

t= 10 s

Car start from rest , u=0 m/s

We know that

$S=ut+\dfrac{1}{2}at^2$

$S=0+\dfrac{1}{2}\times 2\times 10^2$

S= 100 m.

For portion BC:

V= u + at

V=0 + 2 x 10

V= 20 m/s

In this portion car moves with constant velocity 20 m/s for 10 s.

So distance S= V x t

S=20 x 10 =200 m.

For portion CD:

The velocity at point C will be 20 m/s

In this portion the final speed of car will be zero because given that at final car come to rest.

So the acceleration will be in the negative direction to stop the car.

We know that

$v^2=u^2-2aS$

$0=20^2-2\times 2\times S$

S=100 m

The total distance AD=AB + BC+ CD

AD=100 +200 + 100 m

AD=400 m.

The total distance will be 400 m.

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3 years ago

What change of state occurs during vaporization? liquid to gas gas to liquid solid to liquid liquid to solid

nignag [31]

Answer:

A is correct!

Explanation:

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3 years ago

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What would happen to the apparent change in mass if the direction of the current is reversed?

pantera1 [17]

When you reverse the direction of the current, the current loop generated by the magentic field is revered.

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4 years ago