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Tju [1.3M]
3 years ago
6

Supposing you were in space..in a weightless environment, would it require a force to set an object in motion? Explain..

Physics
1 answer:
Dvinal [7]3 years ago
8 0

Answer:

Yes, a force is require to set an object in motion.

Explanation:

  • In space, even if you feel weightless, you are subject to motion. If you are orbiting the Earth, you are under the constant influence of Earth having a free-fall acceleration equal to the centripetal acceleration.
  • To disturb this orbital motion, an external force is required.
  • According to Newton's laws of motion, a force is required to change the state of the rest of a body or to change the velocity or direction if it is moving with uniform velocity along a straight line.
  • Whenever there is a change in velocity or direction of a body there is a force acting on it.
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kipiarov [429]

Answer:

1/f = 1/D' + 1/D

The magnification equation relates the ratio of the image distance and object distance to the ratio of the image height (h^i) and object height (h^o). The magnification equation is stated as follows:

M= H^i/H^o = D^i/D^o

7 0
2 years ago
At a certain distance from a point charge, the potential and electric-field magnitude due to that charge are 4.98 V and 16.2 V/m
son4ous [18]

Answer:

A. 30.7cm

B. 1.7*10^{-10}C

C. The electric field is directed away from the point of charge

Explanation:

A.

 because, E=\frac{v}{d} \\\\d= \frac{4.98}{16.2}\\\\ d = 0.307m\\\\d = 30.7 cm

B.

Considering Gauss's law

EA = \frac{Q}{e}\\\\ where, e = pertittivity. space= 8.85* 10^{-12} Fm^{-1} \\\\A = surface. area. with.radius 0.307m\\Q= eEA = (8.85*10^{-12})(16.2)(4\pi)(0.307)^{2}\\\\= 1.7*10^{-10}C

C. The electric field directed away from the point of charge when the charge is positive.

3 0
3 years ago
A loaded truck is going at a speed of 36 km/hr and a car starts at a point 3 km behind the truck with an acceleration 2 m/s^2 .
kozerog [31]
It's 3600 m and 60 sec
6 0
3 years ago
15) What is the momentum of a 280 kg motorcycle moving with a velocity of 15 m/s?
enot [183]

Answer:

..

Explanation:

6 0
2 years ago
A 2.0 kg bird lands on a 1.0 x 10^1 kg bit of tree bark sitting on a frictionless ice-covered pond. The bird’s initial horizonta
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Here in this type of question we can use momentum conservation

It is because we can see there is no external force on the system

So we can use momentum conservation principle

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

here we know that

m_1 = 2 kg

v_{1i} = 6 m/s

m_2 = 1 * 10^1 kg

v_{2i} = 0

now after bird sits on it then final speed of the both will be same

v_{2f} = v_{1f} = v m/s

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12 = 12*v

v = 1 m/s

so final speed will be 1 m/s

7 0
2 years ago
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