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Mrac [35]
3 years ago
11

Calculate the heat that must be supplied to

Chemistry
1 answer:
Marat540 [252]3 years ago
5 0

Answer:

Q must be supplied = 119523.3~J

Explanation:

The law of conservation of energy can be applied to heat changes, i.e. the heat received/absorbed is the same as the heat released  

Q in = Q out  

Heat can be calculated using the formula:  

Q = mc∆T  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

So from the question :

Q to the system(Q supplied) = Q water + Q steel vessel(Q gained)

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If a object has a mass of 10 kilograms, how much does it weigh in newtons?
Len [333]
Depends on where the object is. On earth, moon , or somewhere without any other mass (theoretically). I think you mean how much does weigh on earth. So, the average gravitational acceleration on earth is : 9.83 m/s^2 To find out how much an object weighs, this is the formula : G=m.g where m is mass of the object g is the gravitational acceleration and G is weight. So, G = 10.9,83 = 98,3 N is the answer.
5 0
3 years ago
A compound is 2.00% H by mass, 32.7% S by mass, and 65.3% O by mass. What is its empirical formula? The first step is to calcula
Georgia [21]
For a 100-g compound, we would have 2 g H, 32.7 g S, and 65.3 g O. We then divide each of these masses by their molar masses:
2 g H / 1.01 g/mol = 1.98 mol H
32.7 g S / 32.07 g/mol = 1.0196 mol S
65.3 g O / 16.00 g/mol = 4.08125 mol O
We then divide each amount of moles by the smallest of them, which is the 1.0196 from S:
1.98 mol H / 1.0196 mol S = 1.94 H ~ 2 H
1.0196 mol S / 1.0196 mol S = 1 S
4.08125 mol O / 1.0196 mol S = 4 O
So the empirical formula of the compound is H2SO4.
7 0
3 years ago
Read 2 more answers
A chemistry student weighs out 0.09666 g of phosphoric acid (H3PO4), a triprotic acid, into a 250.volumetric flask and dilutes t
Ber [7]

Answer: 14.62 ml

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute  

V_s = volume of solution in ml = 250 ml

{\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{0.09666g}{98g/mol}=9.9\times 10^{-4}

Now put all the given values in the formula of molarity, we get

Molarity=\frac{9.9\times 10^{-4}\times 1000}{250ml}

Molarity=3.9\times 10^{-3}M

To calculate the volume of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_3PO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=3\\M_1=3.9\times 10^{-3}M\\V_1=250mL\\n_2=1\\M_2=0.2000M\\V_2=?

Putting values in above equation, we get:

3\times 3.9\times 10^{-3}\times 250=1\times 0.2000\times V_2\\\\V_2=14.62ml

Thus the volume of NaOH solution the student will need to add to reach the final equivalence point is 14.62 ml

8 0
3 years ago
Please!! Very glad if u help!!!!
tiny-mole [99]
I think the answer is either C or D. Hope this helps!
5 0
3 years ago
6.
AveGali [126]
It’s 172 and you gotta divide it lol sorry I need help
3 0
3 years ago
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