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mestny [16]
3 years ago
6

A balloon contains helium with a mass of 0.00296 g. What is the volume of helium in the balloon? (Note: Helium’s density is 0.00

001663 g/cm3.) Volume: 0.00296g/0.00001663g/cm^3 = 177.991581cm^3
Physics
1 answer:
Over [174]3 years ago
7 0

Answer:

178 cm3

Explanation:

From definition of density, it is mass per unit volume of an object, expressed as density=mass/volume and making volume the subject of the above formula we have volume= mass/density and substituting 0.00296 g for mass and 0.00001663 g/cm3 for density then we have

Volume=0.00296/0.00001663

Volume is approximately 178 cm3

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What represents the impulse of the force in a graph of force versus time?
vovikov84 [41]
In the graph of the force vs the time:
Force is the gradient of the momentum versus the time.

If we get the area under the curve in this graph:
it will be calculated as : force * time
which gives the change in momentum or the impulse.

Therefore, the area under the curve <span>represents the impulse of the force in a graph of force versus time</span>
7 0
4 years ago
-Para lograr que una pieza de 0,300 kg de cierto metal aumente su temperatura desde 40°C a 60 °C ha sido necesario suministrarle
marishachu [46]

Answer:

parte a) el calor específico es c = 0.383 J /(gr*K)

parte b) la temperatura inicial es T inicial= 52.72 °C

Explanation:

para el primer punto la formula para el calor Q es:

Q = m * c * ( T final - T inicial )

donde

m= masa de la pieza = 0.300 kg = 300 gr

Q = flujo de energía en forma de calor= 2299 J

c = calor específico

T final = temperatura final =40°C

T inicial = temperatura inicial = 60 °C

entonces

Q = m * c * ( T final - T inicial )

c = Q / [ m* ( T final - T inicial ) = 2299 J/[ 300 gr  * ( 60 °C - 40°C )]

= 0.383 J /(gr*K)

c = 0.383 J /(gr*K)

para el segundo punto usamos la misma formula

Q = m * c * ( T final - T inicial )

pero

m= 200 gr= 0.200 kg

c=459.8 J/(kg*K) , Q =20.900 J , T final = 280 °C

Q = m * c * ( T final - T inicial )

T inicial = T final - Q/(m*c)  =280 °C - 20.900 J/(459.8 J/(kg*K)* 0.200 kg) = 52.72 °C

7 0
4 years ago
A toy car of mass 0.15kg accelerates from a speed of 10 cm/s to a speed of 15 cm/s. What is the impulse acting on the car?
OLga [1]

v=v2-v1=15-10=5 cm/s

p=mv=0.15•5=0.75 kg•cm/s

7 0
4 years ago
Read 2 more answers
Suppose you have a glider and a hanging mass that you wish to know the masses of but you do not have a triple-beam balance avail
AlladinOne [14]

Answer:

the choice of a glider to hanging mass is a ratio of 20.2

Explanation:

The Newton´s second law for glider is:

Fnet=Ma

T=Ma

The Newton´s second law for hanging mass is:

Fnet=ma

mag-T=ma

Replacing:

mag-Ma=ma (eq. 1)

Clearing a:

a=(mg)/(m+M)

The expression for motion is:

y=vot+\frac{1}{2}at^{2}

H=0+\frac{1}{2}at^{2}

Clearing a:

a=\frac{2H}{t^{2} }

Replacing values:

a=\frac{2*0.75}{1.8^{2} } =0.46

From eq. 1:

M/m=20.2

5 0
3 years ago
A powerful motorcycle can accelerate from rest to 24.8 m/s (55 mi/h) in only 5.90 s. (a) What is its average acceleration in m/s
mel-nik [20]

Answer

given,

initial speed,u = 0 m/s

final speed,v = 24.8 m/s

time, t= 5.9 s

a) acceleration,

a=\dfrac{v-u}{t}

a=\dfrac{24.8 - 0}{5.9}

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b) distance to travel in that time

using equation of motion

   v² = u² + 2 as

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       8.4 s = 615.04

          s = 73.22 m

the motorcycle will travel 73.22 m

6 0
4 years ago
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