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DanielleElmas [232]
4 years ago
5

A substance has a half-life of 10,000 years and an initial mass of 1,000 grams. How many years will pass before only 250 grams o

f the substance's parent material is left?
A. 20,000
B.25,000
C. 30,000
D.40,000
Physics
2 answers:
solmaris [256]4 years ago
6 0
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ After 10,000 years the mass will be:

1,000 / 2 = 500

After 20,000 years the mass will be:

500/2 = 250

As you can see, the correct answer would be A. 20,000 years

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

Pavel [41]4 years ago
4 0

Answer:

A). t = 20,000 years

Explanation:

Half life is the total time after which the substance will decay and remains only half of the initial amount

So here we will say that

initial amount is 1000 gram

Now after one half life only half of the amount will remain

so it is

m_1 = 1000/2 = 500 gram

now again after another half life it will remain half of the initial amount

so it is

m_2 = 500/2 = 250 gram

so it took two half lives

t = 10,000 + 10,000

t = 20,000 years

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And gravitational force is given by

F = \frac{G.m_{1}.m_{2}}{r^{2}}

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Now since the planets, stars and galaxies are electrically neutral, therefore they have zero electrical charge and so electro magnetic forces have no affect on  these planets, stars and heavenly bodies.

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8 0
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Newton’s third law is the law of
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3 years ago
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A typical cell phone charger is rated to transfer a maximum of 1.0 Coulomb of charge per second. Calculate the maximum number of
Alexandra [31]

Answer:

The maximum no. of electrons- 2.25\times 10^{22}

Solution:

As per the question:

Maximum rate of transfer of charge, I = 1.0 C/s

Time, t = 1.0 h = 3600 s

Rate of transfer of charge is current, I

Also,

I = \frac{Q}{t}

Q = ne

where

n = no. of electrons

Q = charge in coulomb

I = current

Thus

Q = It

Thus the charge flow in 1. 0 h:

Q = 1.0\times 3600 = 3600\ C

Maximum number of electrons, n is given by:

n = \frac{Q}{e}

where

e = charge on an electron = 1.6\times 10^{- 19}\ C

Thus

n = \frac{3600}{1.6\times 10^{- 19}} = 2.25\times 10^{22}

3 0
4 years ago
A 120 W lightbulb and a 90 W lightbulb each operate at a voltage of 120 V. Part A Which bulb carries more current? Which bulb ca
uysha [10]

Answer:

120 W lightbulb

Explanation:

Let the two lightbulb be A and B respectively.

Given the following data;

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a. For lightbulb A

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b. For lightbulb B

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Therefore, the lightbulb that carries more current is A with 1 Ampere.

7 0
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