From the calculations, the final momentum of B is 8.16 m/s
<h3>What is conservation of linear momentum?</h3>
According to the principle of the conservation of linear momentum, the momentum before collision is equal to the total momentum after collision.
This implies that;
MaUa + MbUb = MaVa + MaVa
Substituting values;
(0.08 kg * 0.5 m/s) + (0.05 kg * 0 m/s) = (0.08 kg * −0.1 m/s) + (0.05 kg * v)
0.4 = -0.008 + 0.05v
v = 8.16 m/s
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A) The resultant force is 30.4 N at 
B) The resultant force is 18.7 N at 
Explanation:
A)
In order to find the resultant of the two forces, we must resolve each force along the x- and y- direction, and then add the components along each direction to find the components of the resultant.
The two forces are:
at
above x-axis
at
above y-axis
Resolving each force:


So, the components of the resultant are:

And the magnitude of the resultant is:

And the direction is:

B)
In this case, the 15 N is applied in the opposite direction to the 20 N force. Therefore we need to re-calculate its components, keeping in mind that the angle of the 15 N force this time is

So we have:

So, the components of the resultant this time are:

And the magnitude is:

And the direction is:

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