Fission creates large amounts of: A.uranium B.air pollution C.carbon dioxide D.radioactive waste
2 answers:
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Assuming the number of moles give is of CO₂, since we know that 1 mol is equivalent to 22.4 L in this case, we can use rule of three to answer this:
V ---- n
x ---- 3.75 mol
22.4 L ---- 1 mol
So, we have the follwing relation:
So, we need a volume of 84 L.
Answer:
²⁵ Mg = 10.00%
²⁶ Mg = 11.0%
Explanation:
Given that:
Magnesium ²⁴Mg has an abundance of 78.99%
Hence, (100 - 78.99)% = 21.01%
21.01% is the abundance of ²⁵ Mg and ²⁶ Mg
Suppose,
²⁵ Mg = x
²⁶ Mg = (21.01 - x)%
Then;
avg. atomic mass =
where the avg. atomic mass = 24.3050
∴
2430.5 = 2440.46915 -0.9968 x
0.9968x = 2440.46915 - 2430.5
0.9968x = 9.96915
x = 9.96915/0.9968
x = 10.00%
∴ Recall that:
²⁵ Mg = x
²⁶ Mg = (21.01 - x)%
²⁵ Mg = 10.00%
²⁶ Mg = (21.01 - 10.00)%
²⁶ Mg = 11.0%