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posledela
3 years ago
5

Number 31 how much is the postage for a 75 ounce package

Mathematics
1 answer:
brilliants [131]3 years ago
4 0

75 oz package

10ozs at .25

leaves you with 65oz at .30, so 7x.30 = 2.10

2.10 + .25 = 2.35

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HELP 7th grade math
Charra [1.4K]
1,920? I think .......
5 0
3 years ago
Read 2 more answers
Find the measures of EAF DAE and CAD
sdas [7]
You have to build an equation to find the answer,

angles in a straight line add upto 180° 
so your equation would be,

12x+30°=180°
      -30    -30
=12x=150°
   ÷12  ÷12
=x=12.5°

now find the measures of the angles by using 12.5 as x.

angle EAF= 2x
                 =2×12.5
                 =25° degrees

angle DAE= 4x
                 =4×12.5
                 =50°degrees

angle CAD=6x
                 =6×12.5
                 =75°degrees

check,
30+25+50+75=180°degrees

hope this helps.......
7 0
3 years ago
What is (4c)^2d ?<br> c = 5 and d = 8
Arte-miy333 [17]

Answer:

  3200

Step-by-step explanation:

Replace the variables with their values and do the arithmetic.

  (4·5)²·8 = 20²·8 = 400·8 = 3200

6 0
3 years ago
Please help me!<br> Find the number x such that f(x) =1
STatiana [176]

Answer:

D

Step-by-step explanation:

We have the piecewise function:

f(x) = \left\{        \begin{array}{ll}            -\frac{1}{2}x-1 & \quad x \leq -2 \\            x & \quad x > -2        \end{array}    \right.

And we want to find x such that f(x)=1.

So, let's substitute 1 for f(x):

1 = \left\{        \begin{array}{ll}            -\frac{1}{2}x-1 & \quad x \leq -2 \\            x & \quad x > -2        \end{array}    \right.

This has two equations. So, we can separate them into two separate cases. Namely:

1=-\frac{1}{2}x-1\text{ or } 1=x

Let's solve for x in each case.

Case I:

We have:

1=-\frac{1}{2}x-1

Add 1 to both sides:

2=-\frac{1}{2}x

Let's cancel out the fraction by multiplying both sides by -2. So:

2(-2)=(-2)\frac{-1}{2}x

The right side cancels:

-4=x\\

Flip:

x=-4

So, x is -4.

Case II:

We have:

1=x

Flip:

x=1

This is the solution for our second case.

So, we have:

x_1=-4\text{ or } x_2=1

Now, can check to see if we have to to remove solution(s) that don't work.

Note that x=-4 is the solution to our first equation.

The first equation is defined only if x is less than -2.

-4 <em>is </em>less than -2. So, x=-4 is indeed a solution.

x=1 is the solution to our second equation.

The second equation is defined only if x is greater than or equal to -2.

1 <em>is</em> greater than or equal to -2. So, x=1 is <em>also </em>a solution.

Therefore, our two solutions are:

x_1=-4\text{ or } x_2=1

Out of our answer choices, we can pick D.

And we're done!

7 0
3 years ago
The baby weighed 7.25 pounds at birth.At the end of 8 months the baby weighed 2 1/2 times its birth weight .How much does the ba
garri49 [273]
Weight at 8 months = 7.25 x 2 1/2
= 7.25 x 5/2
= 7.25 x 2.5
= 18.125

The baby weighs 18.125 pounds at eight months.
6 0
3 years ago
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