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ira [324]
3 years ago
11

In the middle of a turn, you should _____________________. A. brake hard to maintain complete control over your vehicle B. accel

erate abruptly and straighten the wheel C. avoid using your brake or clutch, unless it is necessary to do so in order to avoid a collision D. downshift to allow you to turn more sharply
Physics
1 answer:
Elena L [17]3 years ago
3 0

Answer:

D. Downshift to allow you to turn more sharply

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If the original pressure is 5 atm and original volume is 100 L, and the new volume is 20 L, what is the new pressure?
Nana76 [90]
P1V1=P2V2
5*100=P2*20
500=20P
P=25
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What will happen to the astronaut when the jets produce these four forces: 10N, 10N, 9N, 9N?
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The astronaut would go the opposite direction due to Newton’s third law of -10N, -10N, -9N, -9N

Let me know if this helped you, please rank this was the brainlist answer if possible, thanks!
6 0
3 years ago
during conversion water to ice,forces of attraction between molecules. OPTIONS:1.)Decreases 2.)Increases 3.)Does not change 4.)C
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because water is loosely packed but when it is cold it becomes closely packed in order to form ice and thus the force attraction between them also increase.

4 0
3 years ago
a ford explorer traveled 100 miles the next day for 5 hours. What was the average speed of this vehicle?
Bumek [7]

Answer:

25 miles per hour

Explanation:

4 0
2 years ago
Read 2 more answers
Singly charged uranium-238 ions are accelerated through a potential difference of 2.20 kV and enter a uniform magnetic field of
Aleonysh [2.5K]

Answer:

r = 0.0548 m

Explanation:

Given that,

Singly charged uranium-238 ions are accelerated through a potential difference of 2.20 kV and enter a uniform magnetic field of 1.90 T directed perpendicular to their velocities.

We need to find the radius of their circular path. The formula for the radius of path is given by :

r=\dfrac{1}{B}\sqrt{\dfrac{2mV}{q}}

m is mass of Singly charged uranium-238 ion, m=3.95\times 10^{-25}\ kg

q is charge

So,

r=\dfrac{1}{1.9}\times \sqrt{\dfrac{2\times 3.95\times 10^{-25}\times 2.2\times 10^3}{1.6\times 10^{-19}}}\\\\r=0.0548\ m

So, the radius of their circular path is equal to 0.0548 m.

4 0
2 years ago
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