Answer:
4.3 m/sec
Explanation:
Here height of cliff = y = 37.6 m
Gravitational acceleration = g = 9.8 m/sec2
vi = 0 m/s
Let's find the time which the diver will take if jumps from there!
Using formula
y = vit+1/2gt2
==> 37.6= 0 + 0.5 ×9.8×
==>
=
==> t = 2.8 sec
In this time the diver has to cover a horizontal distance of 12.12 m
If x = 12.12 m is the horizontal distance to be covered then using
x= Vx × t
==> Vx = x/t
==> Vx= 12.12/2.8 = 4.3 m/s
Due to the shape of the lens , parallel rays will be deviated
Explanation:
It is given that,
Diameter of the peach pie, d = 9 inches
Radius of the pie, r = 4.5 inches
The tray is rotated such that the rim of the pie plate moves through a distance of 183 inches, d = 183 inches
Let
is the angular distance that the pie plate has moved through.
It is given by :


Since, 1 radian = 57.29 degrees

Since, 1 radian = 0.159155 revolution

Hence, this is the required solution.