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slava [35]
3 years ago
12

Archer shoots his arrow towards a target at a distance of 90 m and hits bullseye . Calculate the acceleration and time taken by

the arrow to hit the target with a velocity of 90.0 m/s
Physics
1 answer:
goldfiish [28.3K]3 years ago
3 0

Answer:

acceleration = 45 m/s²

Time = 20 seconds

Explanation:

We are given;

Distance; s = 90m

Final velocity;v = 90 m/s

Since shot from rest, initial velocity;u = 0 m/s

So, to find the acceleration, we can use Newton's 2nd law of motion which is;

v² = u² + 2as

Where a is acceleration

Plugging in the values;

90² = 0² + 2a(90)

8100 = 180a

a = 8100/180

a = 45 m/s²

Now, for the time, we will use Newton's 1st law of motion which is;

v = u + at

Where t is time;

So;

90 = 0 + 4.5t

90 = 4.5t

t = 90/4.5

t = 20 seconds

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Answer:

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For isobaric process work done is equal to W=PdV=2.121\times 10^5\times 1.70=3.60\times 10^5J

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