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julsineya [31]
3 years ago
15

How many joules it take to melt 35g of ice at 0

Chemistry
2 answers:
tekilochka [14]3 years ago
8 0
We can't even see half of the question
Yuri [45]3 years ago
6 0
It takes 12,000 Joules of energy to melt 35 grams of ice at 0 °C.
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what is it called when a scientists personal opinion affects the way experimental results are reported?
Monica [59]

I believe the word that you are looking for is "subjective"

-to be influenced by personal opinion or feeling-

PLEASE RATE AS THE BRAINLIEST ANSWER! THANK YOU! :)

4 0
4 years ago
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Which element does this Bohr model represent? (look at a periodic table if needed)
Serjik [45]
Circulating round the nucleus are the electrons in various orbits of different energy levels. Electrons are negatively charged and represented by the symbol 'e'. In the given image the number of protons are -6. Hence the element in question is Carbon as Carbon has the atomic number 6.
6 0
3 years ago
Soda water is water that has bubbles of carbon dioxide in it,
Elan Coil [88]

Answer:

I think mixture

Explanation:

Mixture because it is a mixture of water and carbon

3 0
3 years ago
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What is that the theoretical yield of aluminum oxide I if 3.20 mol of aluminum metal is exposed to 2.70 mole of oxygen
photoshop1234 [79]

Answer:

163.2g

Explanation:

First let us generate a balanced equation for the reaction. This is shown below:

4Al + 3O2 —> 2Al2O3

From the question given, were were told that 3.2moles of aluminium was exposed to 2.7moles of oxygen. Judging by this, oxygen is excess.

From the equation,

4moles of Al produced 2moles of Al2O3.

Therefore, 3.2moles of Al will produce = (3.2x2)/4 = 1.6mol of Al2O3.

Now, let us covert 1.6mol of Al2O3 to obtain the theoretical yield. This is illustrated below:

Mole of Al2O3 = 1.6mole

Molar Mass of Al2O3 = (27x2) + (16x3) = 54 + 48 =102g/mol

Mass of Al2O3 =?

Number of mole = Mass /Molar Mass

Mass = number of mole x molar Mass

Mass of Al2O3 = 1.6 x 102 = 163.2g

Therefore the theoretical of Al2O3 is 163.2g

8 0
3 years ago
A steel container with a movable piston contains 2.00 g of helium which was held at a constant temperature of 25 °C. Additional
shtirl [24]

Answer: D) 1.00 g

Explanation:

According to the Avogadro's law, the volume of gas is directly proportional to the number of moles of gas at same pressure and temperature. That means,

V\propto n

or,

\frac{V_1}{V_2}=\frac{n_1}{n_2}

where,

V_1 = initial volume of gas  = 2.00 L

V_2 = final volume of gas = 3.00 L

n_1 = initial moles of gas  =\frac{\text {Given mass of helium}}{\text {molar mass of helium}}=\frac{2.00g}{4g/mol}=0.500mol

n_2 = final moles of gas  = ?

Now we put all the given values in this formula, we get

\frac{2.00L}{3.00L}=\frac{0.500mol}{n_2}

n_2=0.75mole

Mass of helium =moles\times {\text {molar mass}}=0.75\times 4=3.00g

Thus mass of helium added = (3.00-2.00) g = 1.00 g

4 0
3 years ago
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