Answer:
5.88×10⁸ W
Explanation:
Power = change in energy / time
P = mgh / t
P = (m/t) gh
P = (1.2×10⁶ kg/s) (9.8 m/s²) (50.0 m)
P = 5.88×10⁸ W
The force on a charged particle in a magnetic field is given by
the speed of the charged particle = 10842 m/s.
Explanation:
F= q V B sinθ
F=force=3.5 x 10⁻²N
q= charge= 8.4 x 10⁻⁴ C
B= magnetic field= 6.7 x 10⁻³ T
θ=35⁰
Thus the velocity is given by V=![\frac{F}{q B sin35}](https://tex.z-dn.net/?f=%20%5Cfrac%7BF%7D%7Bq%20B%20sin35%7D%20%20)
V=(3.5 x 10⁻²)/[(8.4 x 10⁻⁴)(6.7 x 10⁻³)(sin35)]
V=10842 m/s
Answer:0.0704 kg
Explanation:
Given
initial Absolute pressure
=210+101.325=311.325
![T_1=25^{\circ}\approx 298 K](https://tex.z-dn.net/?f=T_1%3D25%5E%7B%5Ccirc%7D%5Capprox%20298%20K)
![V=0.025 m^3](https://tex.z-dn.net/?f=V%3D0.025%20m%5E3)
![T_2=50^{\circ}\approx 323 K](https://tex.z-dn.net/?f=T_2%3D50%5E%7B%5Ccirc%7D%5Capprox%20323%20K)
as the volume remains constant therefore
![\frac{P_1}{T_1}=\frac{P_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1%7D%7BT_1%7D%3D%5Cfrac%7BP_2%7D%7BT_2%7D)
![\frac{311.325}{298}=\frac{P_2}{323}](https://tex.z-dn.net/?f=%5Cfrac%7B311.325%7D%7B298%7D%3D%5Cfrac%7BP_2%7D%7B323%7D)
![P_2=337.44 KPa](https://tex.z-dn.net/?f=P_2%3D337.44%20KPa)
therefore Gauge pressure is 337.44-101.325=236.117 KPa
Initial mass ![m_1=\frac{P_1V}{RT_1}=\frac{311.325\times 0.025}{0.0287\times 298}](https://tex.z-dn.net/?f=m_1%3D%5Cfrac%7BP_1V%7D%7BRT_1%7D%3D%5Cfrac%7B311.325%5Ctimes%200.025%7D%7B0.0287%5Ctimes%20298%7D)
![m_1=0.91 kg](https://tex.z-dn.net/?f=m_1%3D0.91%20kg)
Final mass ![m_2=\frac{P_2V}{RT_2}=\frac{311.325\times 0.025}{0.0287\times 323}](https://tex.z-dn.net/?f=m_2%3D%5Cfrac%7BP_2V%7D%7BRT_2%7D%3D%5Cfrac%7B311.325%5Ctimes%200.025%7D%7B0.0287%5Ctimes%20323%7D)
![m_2=0.839](https://tex.z-dn.net/?f=m_2%3D0.839)
Therefore
=0.91-0.839=0.0704 kg of air needs to be removed to get initial pressure back
Balance them that's the reason why