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mixer [17]
3 years ago
11

Which statement describes the distribution of charge in an atom? (1) A positively charged nucleus is surrounded by one or more n

egatively charged electrons. (2) A positively charged nucleus is surrounded by one or more positively charged electrons. (3) A neutral nucleus is surrounded by one or more negatively charged electrons. (4) A neutral nucleus is surrounded by one or more positively charged electrons.
Physics
2 answers:
SashulF [63]3 years ago
6 0

Answer:

(1) A positively charged nucleus is surrounded by one or more negatively charged electrons.

Explanation:

An atom is the smallest indivisible part of an element which retains all the chemical properties of that element.

Atoms are usually made up of a nucleus which consists of  positively charged proton(s) and neutral neutron(s) and surrounded by an equal amount of negatively charged electrons located at a distance, r called its atomic radius.

The number of positively charged protons equals the number of negatively charged electrons, thus making the atom electrically neutral.

So, the distribution of charge in an atom is thus one in which a positively charged nucleus is surrounded by one or more negatively charged electrons.

pantera1 [17]3 years ago
4 0

Answer: option B

Explanation: when a neutral atom loses an electron or gains a positive charge electron, it becomes a positive ion (positively charged) and when an neutral atom gains an electronic charge or losses a positive charge electron, it becomes a negative ion (negatively charged).

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A (20*20) cm² loop has a resistance of 0.10 Ω. A magnetic field perpendicular to the loop is B = 4t - 2t², where B is in tesla a
Ilya [14]

Answer with Explanation:

We are given that

Area of loop=(20\times 20) cm^2=400\times 10^{-4} m^2

1 cm^2=10^{-4} m^2

Resistance, R=0.1\Omega

B=4t-2t^2

We know that magnetic flux

\phi=BA

Emf ,E=\mid \frac{d\phi}{dt}\mid =\mid\frac{d(BA}{dt}\mid =\mid A\frac{dB}{dt}=400\times 10^{-4}\times \frac{4t-2t^2}{dt}\mid =\mid400\times 10^{-4}\times(4-4t)\mid

Current, I=\frac{E}{R}

Current, I=\frac{\mid 400\times 10^{-4}(4-4t)\mid }{0.1}=1.6\mid (1-t)\mid

Substitute t=0 s

Then, I=1.6\mid (1-0)\mid=1.6 A

Substitute t=1 s

Then, I=1.6\mid (1-1)\mid=0

Substitute

t=2 s

Current, I=1.6\mid(1-2)\mid=1.6 A

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3 years ago
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3 years ago
Fiber optics are an important part of our modern internet. In these fibers, two different glasses are used to confine the light
motikmotik

Answer:

n_cladding = 1.4764

Explanation:

We are told that θ_max = 5 °

Thus;

θ_max + θ_c = 90°

θ_c = 90° - θ_max

θ_c = 90° - 5°

θ_c = 85°

Now, critical angle is given by;

θ_c = sin^(-1) (n_cladding/n_core)

sin θ_c = (n_cladding/n_core)

n_cladding = (n_core) × sin θ_c

Plugging in the relevant values, we have;

n_cladding = 1.482 × sin 85

n_cladding = 1.4764

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