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3 years ago

Please answer these questions 30 points

Physics

2 answers:

Maksim231197 [3]3 years ago

6 0

Answer:

if i were you i would try to do the work because if you let someone else you wont be able to understand the question

Talja [164]3 years ago

5 0

Hello There!

Where is fluid pressure greatest? "2 meters below the surface of a swimming pool."

#13 "the weight of the fluid displaced by the object"

#14 25 N•m

#15 "5"

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Calculate the pressure on the ground from an 80 kg woman leaning on the back of one of her shoes with a 1cm diameter heel, and c

rodikova [14]

Answer:

Pressure of woman will be $99.87\times 10^5N/m^2$

Pressure of the elephant will be $1716560.50N/m^2$

Explanation:

We have given that mass of the woman m = 80 kg

Acceleration due to gravity $g=9.8m/sec^2$

Diameter of shoes = 1 cm =0.01 m

So radius $r=\frac{d}{2}=\frac{0.01}{2}=0.005m$

So area $A=\pi r^2=3.14\times 0.005^2=7.85\times 10^{-5}m^2$

We know that force is given F = mg

So $F=80\times 9.8=784N$

Now we know that pressure is given by $P=\frac{F}{A}=\frac{784}{7.85\times 10^{-5}}=99.87\times 10^5N/m^2$

Now mass of elephant m = 5500 kg

So force of elephant = 5500×9.8 = 53900 N

Diameter = 20 cm

So radius r = 10 cm

So area will be $A=3.14\times 0.1^2=0.0314m^2$

So pressure will be $P=\frac{53900}{0.0314}=1716560.50N/m^2$

3 0

3 years ago

A 3-kg chunk of putty moving at 2 m/s collides with and sticks to a 5-kg bowling ball initially at rest. The bowling ball and pu

Oduvanchick [21]

Answer:

It's Momentum becomes 4

4 0

3 years ago

Where is there potential energy in this system?

mario62 [17]

In the air and the metal

4 0

3 years ago

Read 2 more answers

To understand the decibel scale. The decibel scale is a logarithmic scale for measuring the sound intensity level. Because the d

frez [133]

The question is incomplete. Here is the complete question.

To understand the decibel scale. The decibel scale is a logarithmic scale for measuring the sound intensity level. Because the decibel scale is logarithmic, it changes by an additive constant when the intensity when the intensity as measured in W/m² changes by a multiplicative factor. The number of decibels increase by 10 for a factor of 10 increase in intensity. The general formula for the sound intensity level, in decibels, corresponding to intensity I is

$\beta=10log(\frac{I}{I_{0}} )dB$ ,

where $I_{0}$ is a reference intensity. for sound waves, $I_{0}$ is taken to be $10^{-12} W/m^{2}$ . Note that log refers to the logarithm to the base 10.

Part A: What is the sound intensity level β, in decibels, of a sound wave whose intensity is 10 times the reference intensity, i.e. $I=10I_{0}$ ? Express the sound intensity numerically to the nearest integer.

Part B: What is the sound intensity level β, in decibels, of a sound wave whose intensity is 100 times the reference intensity, i.e. $I=100I_{0}$ ? Express the sound intensity numerically to the nearest integer.

Part C: Calculate the change in decibels ( $\Delta \beta_{2},\Delta \beta_{4}$ and $\Delta \beta_{8}$ ) corresponding to f = 2, f = 4 and f = 8. Give your answer, separated by commas, to the nearest integer -- this will give an accuracy of 20%, which is good enough for sound.

Answer and Explanation: Using the formula for sound intensity level:

A) $I=10I_{0}$

$\beta=10log(\frac{10I_{0}}{I_{0}} )$

$\beta=10log(10 )$

β = 10

The sound Intensity level with intensity 10x is 10dB.

B) $I=100I_{0}$

$\beta=10log(\frac{100I_{0}}{I_{0}} )$

$\beta=10log(100)$

β = 20

With intensity 100x, level is 20dB.

C) To calculate the change, take the f to be the factor of increase:

For $\Delta \beta_{2}$ :

$I=2I_{0}$

$\beta=10log(\frac{2I_{0}}{I_{0}} )$

$\beta=10log(2)$

β = 3

For $\Delta \beta_{4}$ :

$I=4I_{0}$

$\beta=10log(\frac{4I_{0}}{I_{0}} )$

$\beta=10log(4)$

β = 6

For $\Delta \beta_{8}$ :

$I=8I_{0}$

$\beta=10log(\frac{8I_{0}}{I_{0}} )$

β = 9

Change is

$\Delta \beta_{2},\Delta \beta_{4}$ , $\Delta \beta_{8}$ = 3,6,9 dB

6 0

3 years ago

" A 4 kg ball is thrown at an angle of 40 degrees above the horizon from the top of a 150 m cliff. How far from the base of the

TEA [102]

Answer: 180.102m

Explanation:

This situation is a good example of the projectile motion or parabolic motion, in which the travel of the ball after it is thrown from the top of the cliff has two components: x-component and y-component. Being their main equations as follows:

x-component:

$x=V_{o}cos\theta t$ (1)