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pychu [463]
3 years ago
10

A ball is dropped from the top of a 77 m building. With what speed does the ball hit the ground? _________ m/s

Physics
1 answer:
vitfil [10]3 years ago
3 0

Answer:

38.87 m/s

Explanation:

Given that the ball is dropped from a height = 77 m

u = 0 m/s

s = 77 m

a = g = 9.81 m/s²

Applying the expression as:

v^2-u^2=2as

Applying values as:

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 77+0^2}\\\Rightarrow v=38.87\ m/s

<u>The speed with which the ball hit the ground = 38.87 m/s</u>

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g Estimate the number of photons emitted by the Sun in a second. The power output from the Sun is 4 × 1026 W and assume that th
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Answer:

The value is N  =  1.107 *10^{45 }  \ photons    

Explanation:

From the question we are told that

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   The average wavelength of each photon is  \lambda  = 550 \  nm  =  550 *10^{-9} \  m

Generally the energy of each photon emitted is mathematically represented as

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          c is the speed of light with value  c =  3.0 *10^{8} \  m/s

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Generally the  number of photons emitted by the Sun in a second is mathematically represented as

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