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kvv77 [185]
3 years ago
12

How much work is done (in Joules) by a weightlifter in raising a 60-kg barbell from the floor to a height of 2m? Work done =

Physics
2 answers:
Vika [28.1K]3 years ago
7 0

Answer:

1176 Nm or J

Explanation:

W = F*d

F = 60kg * 9.8 kgm/s^2 = 588 N

W = 588 N * 2m = 1176 N*m

Daniel [21]3 years ago
3 0

which question it is so Difflect

Explanation:

please follow me

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The direction of the acceleration of an object on a(n) _______________________ path is toward the _______________________ of the
aleksandrvk [35]

Answer:

circular...center

Explanation:

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8 0
3 years ago
The biggest reason that some fuels are considered nonrenewable
zhuklara [117]
Because many fuels are fossil fuels they take millions of years to form and the known reserves are being used much faster than the new ones being made
4 0
3 years ago
Which conditions must be met in order for work to be done?​
Anettt [7]

Answer:

u wanna do my edge bro the answer is b

Explanation:

3 0
3 years ago
Your friend, Tim, is playing with his sled. He ties a rope to his sled and attaches it to Lar's snowmobile. Tim has a mass of 71
kykrilka [37]

The maximum speed of Tim is 16.95 m/s.

The given parameters:

  • Mass of the rope, m = 71 kg
  • Tension on the rope, T = 220 N
  • Coefficient of kinetic friction, = 0.1
  • Time of motion, t = 8 s

<h3>What is Newton's second law of motion?</h3>
  • Newton's second law of motion states that, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

The net force on Tim is calculated by applying Newton's second law of motion as follows;

T - \mu _k F_n = ma\\\\T - \mu _k F_n = m\frac{v}{t} \\\\T - \mu_k mg = m\frac{v}{t} \\\\t(\frac{T - \mu_k mg}{m} )= v\\\\8 (\frac{220 \ -\  0.1 \times 71 \times 9.8}{71} ) =v \\\\ 16.95 \ m/s = v

Thus, the maximum speed of Tim is 16.95 m/s.

Learn more about net horizontal force here: brainly.com/question/21684583

7 0
2 years ago
A ball is dropped from a height of 20m and renounce with the velocity which is 3/4 of d velocity with which it hits the ground.
Mashutka [201]

Answer:

1.73 seconds

Explanation:

The velocity the ball first hits the ground with is:

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (-10 m/s²) (-20 m)

v = -20 m/s

The velocity it rebounds with is 3/4 of that in the opposite direction, or 15 m/s.

The time it takes to return to the ground is:

Δx = v₀ t + ½ at²

0 = (15 m/s) t + ½ (-10 m/s²) t²

0 = t (15 − 5t²)

t = √3

t ≈ 1.73 seconds

3 0
3 years ago
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