Answer: The empirical formula for the given compound is 
Explanation : Given,
Percentage of C = 38.8 %
Percentage of H = 16.2 %
Percentage of N = 45.1 %
Let the mass of compound be 100 g. So, percentages given are taken as mass.
Mass of C = 38.8 g
Mass of H = 16.2 g
Mass of N = 45.4 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Carbon =
Moles of Hydrogen = 
Moles of Nitrogen = 
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.23 moles.
For Carbon = 
For Hydrogen = 
For Oxygen = 
Step 3: Taking the mole ratio as their subscripts.
The ratio of C : H : N = 1 : 5 : 1
Hence, the empirical formula for the given compound is 
V1 = 445ml V2 = 499ml
T1 = 274 K T2 = ?
By Charles Law,
V1/T1 = V2/T2
445/274 = 499/T2
By solving we get,
T2 = 307.25 K
Answer:
2.3
Explanation:
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When collecting gas over water, the gas is always a mixture of the gas collected and water vapor. This statement is true.
The gaseous phase of water is known as water vapor or aqueous vapor. Within the hydrosphere, it is one type of water state. Water vapor can be created by the boiling or evaporation of liquid water as well as by the sublimation of ice. Like the majority of other atmospheric elements, water vapor is transparent. The mist that hovers above a saucepan of boiling water is an illustration of water vapor.
Gaseous water, particularly when it is distributed in the atmosphere. Steam. The most frequent greenhouse gas is water vapor. It contributes to around half of the planet's warming. It absorbs heat that is projected upward from the earth while letting practically all sunlight reach the planet's surface like other greenhouse gases do.
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brainly.com/question/20899075
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