Answer:
The correct answer is option B.
Explanation:
Moles of 
= 40 mol
Moles of NaOH = 48 mol
According to reaction, 3 moles of NaOH reacts with 2 moles
Then ,48 moles of NaOH will reacts with:
of
Then ,40 moles of 
will reacts with:
of NaOH
As we can see that 48 moles of sodium will completey react with 32 moles of nitrogen tribromide.
Moles left after reaction = 40 mol - 32 mol = 8 mol
Hence, the is an excessive reagent.
Answer:- 1337 g
Solution:- For mathematical operations we use PEMDAS. P stands for parenthesis off, E stands for exponents, M stands for multiplication, D stands for division, A stands for addition and S stands for subtraction. All the mathematical operations are done in this sequence.
What we have given in the problem is, 1210.0 g + 157.22 g - 30. g
Here we have addition and subtraction. As per the law, we will do addition first. In addition and subtraction we go with least number of decimal places.
1210.0 has one decimal place where as 157.22 has two decimal places, since the first number has least decimal places(one decimal place), the answer should also have only one decimal place.
1210.0 g + 157.22 g = 1367.2 g
Now, we will do subtraction. 30. does not have any decimal place and so on subtraction the final answer must not have any decimal places.
1367.2 g - 30. g = 1337 g
So, the final answer is 1337 g.
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