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dem82 [27]
3 years ago
5

What kind of properties can only be observed when a substance changes into a different substance? physical properties reaction p

roperties chemical properties changing properties
Chemistry
2 answers:
Vitek1552 [10]3 years ago
8 0

When a substance changes into a different substance, you are observing its chemical properties.

In a physical change, the substance must <em>not </em>change into a different substance.

The physical and chemical properties of a substance do <em>not</em> change.

balu736 [363]3 years ago
7 0
<h3>Answer:</h3><h2>C. Chemical properties</h2><h3>Explanation:</h3>

By its very definition, a chemical property is one which is exhibited as a result of a chemical reaction. This may happen during or after the reaction. This is because in a chemical reaction there is a transformation in the physical composition of the components and this directly affects its chemical properties.

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pashok25 [27]

Answer:

B. halocline

Explanation:

it is a zone in the oceanic water that changes depending on the depth

Hope This Helped Sorry If Wrong

6 0
2 years ago
21.10g of NaOH and Ba3(OH)2 mixture is dissolved water to prepare 1.0dm³ Solution. To neutralize 25.OO mL of this solution needs
alex41 [277]

From the equation of te reaction, we know that the mass percent  of NaOH in the mixture is 1.4%.

<h3>What is neutralization?</h3>

Neutralization is a reaction that occurs between an acid and a base to yield salt and water only.

In tis case, the reaction of the NaOH and HCl occurs as follows; NaOH + HCl ----> NaCl + H2O

Number of moles of HCl reacted = 15/1000 * 0.5 moldm-³ = 0.0075 moles

Since the reaction is 1:1, 0.0075 moles of NaOH reacted.

Mass of NaOH =  0.0075 moles of NaOH * 40 g/mol = 0.3 g

Percent of NaOH = 0.3 g/21.10g * 100/1 = 1.4%

Learn more about percent concentration: brainly.com/question/202460

8 0
2 years ago
Which statement is true about A nickel-cadmium dry cell?
marusya05 [52]

Answer:

The cathode reaction is NiO2+H2O+2e−→Ni(OH)2+2OH−.

4 0
2 years ago
Consider the following chemical reaction: H2 (g) + I2 (g) 2HI (g) At equilibrium in a particular experiment, the concentrations
bearhunter [10]

The question is incomplete, here is the complete question:

Consider the following chemical reaction: H₂ (g) + I₂ (g) ⇔ 2HI (g) At equilibrium in a particular experiment, the concentrations of H₂, I₂, and HI were 0.15 M, 0.033 M and 0.55 M respectively. The value of Keq for this reaction is

<u>Answer:</u> The value of K_{eq} for the given reaction is 61.11

<u>Explanation:</u>

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_[eq}

For a general chemical reaction:

aA+bB\rightarrow cC+dD

The expression for K_{eq} is written as:

K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

For the given chemical equation:

H_2(g)+I_2(g)\rightleftharpoons 2HI(g)

The expression of K_{eq} for above equation follows:

K_{eq}=\frac{[HI]^2}{[H_2][I_2]}

We are given:

[HI]_{eq}=0.55M

[H_2]_{eq}=0.15M

[I_2]_{eq}=0.033M

Putting values in above expression, we get:

K_{eq}=\frac{(0.55)^2}{0.15\times 0.033}\\\\K_{eq}=61.11

Hence, the value of K_{eq} for the given reaction is 61.11

4 0
4 years ago
Organic chemistry please help ​
lord [1]
The answer to this is C. III & IV
3 0
4 years ago
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