During a track and field event, a metal javelin (not infinitesimally thin) is thrown due east and parallel to the ground. At the
field where the event took place, the magnetic field is running straight up and perpendicular to the ground. In which direction will the current flow in the metal object?
1 answer:
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Answer:
1472.98 m
Explanation:
Data provided:
Speed of circular looping, v = 340 m/s
Acceleration, a = 8g
here,
g is the acceleration due to the gravity = 9.81 m/s²
Now,
the centripetal acceleration is given as,
r is the radius of the loop
on substituting the respective values, we get
or
r = 1472.98 m
Answer:
Please refer to the figure.
Explanation:
The crucial point here is to calculate the enclosed current. If the current I is flowing through the whole cross-sectional area of the wire, the current density is
The current density is constant for different parts of the wire. This idea is similar to that of the density of a glass of water is equal to the density of a whole bucket of water.
So,
This enclosed current is now to be used in Ampere’s Law.
Here, represents the circular path of radius r. So we can replace the integral with the circumference of the path,
.
As a result, the magnetic field is
