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slega [8]
3 years ago
8

Which of the three components of the atom has the smallest mass?

Chemistry
1 answer:
Lesechka [4]3 years ago
8 0
Electron has the smallest mass
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A cork has a mass of 3 grams and a volume of 16 cms calculate the density
REY [17]

hey mate here is ur answer

solution

mass{m}=3 gram

             =3/1000

             

volume{v}=16cm

                =16/100

               

density=m/v

           =3/1000÷16/100

           =3/160

            =0.01875kg/m3

6 0
3 years ago
The smallest unit that can exist as an element and still have the properties of that element is a(n):
Yuri [45]
The smallest unit that can exist as an element and still have proprieties of that element is an Atom<span />
8 0
2 years ago
Read 2 more answers
When a pendulum swings, if it is not continuously pushed it will not stop eventually because some of its energy is changed into.
Vladimir79 [104]
Well, there is kinetic energy when the object is in motion. But it will stop eventually because that energy is converted into thermal energy, or heat.
7 0
2 years ago
Lead can be prepared from galena [lead(II) sulfide] by first roasting the galena in oxygen gas to form lead(II) oxide and sulfur
Vesna [10]

Answer:

a) Step 1:

2PbS(g)+3O_2(g)\overset{roasting}\rightarrow 2PbO(s)+2SO_2(g)

Step 2:

2PbO(s)+PbS(s)\overset{\Delta }\rightarrow 3Pb(l)+SO_2(g)

b) The overall balanced reaction for given process is ;

3PbS(s)+3O_2(g)\rightarrow 3Pb(l)+3SO_2(g)

Explanation:

a)

Galena = PbS

Lead(II) oxide = PbO

Sulfur dioxide = SO_2

Step 1:

Roasting the galena in oxygen gas to form lead(II) oxide and sulfur dioxide.

Balanced equation of step 1:

2PbS(g)+3O_2(g)\overset{roasting}\rightarrow 2PbO(s)+2SO_2(g)..[1]

Step 2:

Heating the metal oxide with more galena forms the molten metal and more sulfur dioxide.

Balanced equation of step 2:

2PbO(s)+PbS(s)\overset{\Delta }\rightarrow 3Pb(l)+SO_2(g)..[2]

b)

For over all reaction add [1] and [2]. The overall balanced reaction for given process is ;

3PbS(s)+3O_2(g)\rightarrow 3Pb(l)+3SO_2(g)

5 0
3 years ago
Read 2 more answers
How many moles of butane do we have if we have 5.50 x 1024 molecules<br> of butane (CH) ?
Dmitry [639]

Answer:

9.14moles

Explanation:

Given parameters:

Number of atoms of butane  = 5.5 x 10²⁴atoms

Unknown:

Number of moles  = ?

Solution:

To solve this problem, we must understand that a mole of any substance contains the Avogadro's number of particles.

             6.02 x 10²³ atoms makes up 1 mole of an atom

             5.5 x 10²⁴ atoms will contain = \frac{5.5 x 10^{24} }{6.02 x 10^{23} }  = 9.14moles

7 0
2 years ago
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