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4 years ago

Why is newton's first law of motion sometimes called the lae of inertia?

1 answer:

4 0

Newton's 1st law of motion states that <span>an object at rest stays at rest and an object in uniform motion along a straight line stays in motion unless acted upon by an unbalanced force.
This law talks about the tendency of an object to resist any change in its state of rest or uniform motion, this is called Inertia. Thus Newton's 1st law of motion is also called the Law of Inertia</span>

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Please help quickly,the picture and choices are above.

Setler79 [48]

Answer:

C because it make sens

C the light wave traveled through ice and then through a Dimond.

7 0

2 years ago

A push or pull is called a force. Unbalanced forces can cause objects to move in many ways but not to move faster. B) move slowe

Allushta [10]

Answer:

but not to

D). float in the air

6 0

3 years ago

Answer the following question according to formal grammatical rules.

VARVARA [1.3K]

Answer:

Explanation:

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3 years ago

a 10kg ball is thrown into the air. it is going 3m/s when thrown. How much potential energy will it have at the top?

Alexandra [31]

Answer:

45 J

Explanation:

Assuming the level at which the ball is thrown upwards is the ground level,

We can use the equations of motion to obtain the maximum height covered by the ball and then calculate the potential energy

u = initial velocity of the ball = 3 m/s

h = y = vertical distance covered by the ball = ?

v = final velocity of the ball at the maximum height = 0 m/s

g = acceleration due to gravity = -9.8 m/s²

v² = u² + 2ay

0 = 3² + 2(-9.8)(y)

19.6y = 9

y = (9/19.6)

y = 0.459 m

The potential energy the ball will have at the top of its motion = mgh

mgh = (10)(9.8)(0.459) = 45 J

Hope this Helps!!!

7 0

3 years ago

A circular loop of wire 75 mm in radius carries a current of 113 A. Find the (a) magnetic field strength and (b) energy density

Roman55 [17]

The magnetic field strength is 9.47 ×10⁻⁴ T

The energy density at the center of the loop is 0.36 J/m³

<h3>Calculating Magnetic field strength & Energy density </h3>

From the question, we are to find the magnetic field strength

The magnetic field strength of a loop can be calculated by using the formula,

$B = \frac{\mu_{0} I}{2R}$

Where B is the magnetic field strength

$\mu_{0}$ is the permeability of free space $(\mu_{0}=4\pi \times 10^{-7} \ N/A^{2})$

$I$ is the current

and R is the radius

From the give information,

$R = 75 \ mm= 75 \times 10^{-3} \ m$

and $I = 113 \ A$

Putting the parameters into the formula, we get

$B = \frac{4\pi \times 10^{-7} \times 113}{2 \times 75 \times 10^{-3} }$

$B = 9.47 \times 10^{-4} \ T$

Hence, the magnetic field strength is 9.47 ×10⁻⁴ T

Now, for the energy density

Energy density can be calculated by using the formula,

$u_{B} = \frac{B^{2} }{2\mu_{0} }$

Where $u_{B}$ is the energy density

Then,

$u_{B}= \frac{(9.47\times 10^{-4} )^{2} }{2 \times 4\pi \times 10^{-7} }$

$u_{B} = 0.36 \ J/m^{3}$

Hence, the energy density at the center of the loop is 0.36 J/m³

Learn more on Magnetic field stregth & Energy density here: brainly.com/question/13035557

7 0

2 years ago