Answer:
what is the question? there isn't one
Answer:
The answer is 7.8 kJ / mol.
Explanation:
Energy = (number of methyl group) (Gauche interactions)(3.8kJ/mol per interaction)
= (2)(2)(3.8 kJ / mol)
= 15.2 kJ / mol.
The energy = (number of methyl group) - ( energy of gauche interactions)
= (23 kJ/mol) - 15.2 kJ/mol
= 7.8 kJ / mol.
Answer:
The hydro static force on the back of the dam is 
Explanation:
Given that,
Width b= 1000 m
Depth d= 200 m
We need to calculate the average pressure
Using formula of average pressure
Put the value into the formula
We need to calculate the hydro static force on the back of the dam
Using formula of force
Put the value into the formula
Hence, The hydro static force on the back of the dam is
So if the formula for work is force times displacement times cosine(theta), you'd plug in the numbers
100x5 (since there's no angle in the problem, cosine(theta) isn't used
100x5 = 500
So the answer would be B.
Hope that helps!
Answer:
B) 1.2 N, toward the center of the circle
Explanation:
The circumference of the circle is:
C = 2πr
C = 2π (0.70 m)
C = 4.40 m
So the velocity of the ball is:
v = C/t
v = 4.40 m / 0.60 s
v = 7.33 m/s
Sum of the forces in the radial direction:
∑F = ma
T = m v² / r
T = (0.015 kg) (7.33 m/s)² / (0.70 m)
T = 1.2 N
The tension force is 1.2 N towards the center of the circle.
