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anygoal [31]
3 years ago
14

The variable placed on the horizontal or x-axis of a graph is what variable

Chemistry
1 answer:
grin007 [14]3 years ago
8 0

Answer:

Independent variable

Explanation:

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Identifying a trend in temperature change over time
stiv31 [10]

Answer:

More than three decade the temperature of earth is increasing equally by the rate of 0.8 Celsius (1.4 Fahrenheit). It is going to be very harmful for the human being as well animals.  The global warming is the main reason and hole in the ozone layer had been the cause of increasing the temperature of the earth. Humans are also involved in cause in temperature of earth by cutting forests and making land suitable for residence and not planting more trees instead of the cut trees.

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3 years ago
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Name the acids present in Tamarind Tomato and Vinegar?​
OverLord2011 [107]

Answer:

<h3>tartaric acids</h3>

The molecular formula of the citric acid is C6H8O7. The structure of citric acid is as follows: The acid present in tamarind is tartaric acid.

<h3>Vinegar- </h3>

Oxalic

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2 years ago
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Balance the equation αC6H14(g)+βO2(g)→γCO2(g)+δH2O(g)
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Answer: The balanced reaction is:
<span>2 C6H14(g)+ 19 O2(g) → 12 <span>CO2</span>(g)+ 14 H2O(g)

Note: While balancing the chemical reaction, care must be taken that total number atoms (of each type) on both reactant and product side must be same. In present case, there are 12 'C' atoms, 28 'H' atoms and 38 'O' atoms on both reactant and product side. Hence, the reaction is balanced. </span>
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3 years ago
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If the [H3O+] of a solution is 1x 10-8 mol/L the [OH-] is
Studentka2010 [4]

Answer:

<em>(H30+)= 1x10^-6 M</em>

Explanation:

Both pH and pOH have a relationship to belonging to the same aqueous solution: the expression of the Kwater (ionic product of the water Kw) is used:

1x 10-8 mol/L equals to1x10-8 M

(H3O+) x (OH-) = 1x10^-14

(H30+)x 1x 10^-8 =1x10^-14

(H30+)= 1x10^-14/1x 10^-8

<em>(H30+)= 1x10^-6 M</em>

6 0
3 years ago
A diver has a lung capacity of 2.4 L when the pressure is 0.8 atm. What is the volume of the diver’s lungs when the pressure cha
tangare [24]

Answer:

The final volume is 1.6 L.

Explanation:

It is given that,

A diver has a lung capacity of 2.4 L when the pressure is 0.8 atm. We need to find the volume of the diver’s lungs when the pressure changes to 1.2 atm. Let V₂ is volume.

It is based on Boyle's law. According to this law,

PV=K

K is constant

P_1V_1=P_2V_2

V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{0.8\times 2.4}{1.2}\\\\V_2=1.6\ L

So, the final volume is 1.6 L.

7 0
3 years ago
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