Answer:
pH = 4.27. Porcentaje de disociación: 0.03%
Explanation:
El pH de un ácido débil, HX, se obtiene haciendo uso de su equilibrio:
HX(aq) ⇄ H⁺(aq) + X⁻(aq)
Donde la constante de equilibrio, Ka, es
Ka = 1.65x10⁻⁸ = [H⁺] [X⁻] / [HX]
Como los iones H⁺ y X⁻ vienen del mismo equilibrio podemos decir:
[H⁺] = [X⁻]
[HX] es:
20g * (1mol/55g) = 0.3636moles / 2.100L = 0.1732M
Reemplazando es Ka:
1.65x10⁻⁸ = [H⁺] [H⁺] / [0.1732M]
2.858x10⁻⁹ = [H⁺]²
5.35x10⁻⁵M = [H⁺]
pH = -log[H⁺]
<h3>pH = 4.27</h3>
El porcentaje de disociacion es [X⁻] / [HX] inicial * 100
Reemplazando
5.35x10⁻⁵M / 0.1732M * 100
<h3>0.03%</h3>
Wavelength relates to frequency as follows: λ=vf in which f is the frequency, v is the speed of light, and λ is the wavelength.
Answer:
A model is developed for predicting oxygen uptake, muscle blood flow, and blood chemistry changes under exercise conditions. In this model, the working muscle mass system is analyzed. The conservation of matter principle is applied to the oxygen in a unit mass of working muscle under transient exercise conditions. This principle is used to relate the inflow of oxygen carried with the blood to the outflow carried with blood, the rate of change of oxygen stored in the muscle myoglobin, and the uptake by the muscle. Standard blood chemistry relations are incorporated to evaluate venous levels of oxygen, pH, and carbon dioxide.
Explanation:
Answer:
1.52 M
Explanation:
Molarity of a solution is calculated as follows:
Molarity = number of moles (n) ÷ volume (V)
Based on the information given in this question,
Volume of soda (V) = 9.13 L
number of moles = 13.83 mol
Molarity = 13.83 ÷ 9.13
Molarity = 1.52 M
The rheo leaf peel will lose water by osmosis and become flaccid. If the rheo leaf was boiled, this would not happen.
<h3>What is osmosis?</h3>
Across living membranes, water moves from a region of high to a region of low water potential.
Concentrated sugar solutions have low water potential when compared to the cell sap of the cells of rheo leaf peel. Thus, water will move from the rheo leaf peel to the sugar solution.
This will result in the wilting of the leaf peel.
If the leaf peel is boiled, the membranes in the cells die and can no longer function as a selectively permeable interface.
More on osmosis can be found here: brainly.com/question/1799974
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