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Crank
3 years ago
10

What is the pH of 1.0M HI solution?

Chemistry
2 answers:
ozzi3 years ago
7 0

Answer:

0

Explanation:

Since HI is a strong acid, the amoung of Hydrogen ions produced by it will be the same molar as the reactant. The negative log of the concentration will reveal that the pH is 0.

ELEN [110]3 years ago
4 0

Answer:

<h2>pH = <u>0</u></h2>

Explanation:

{hope it helps}}

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Which of the following properties would helium have?
Mandarinka [93]

Answer:

B

Explanation:

It is a gas and therefore according to particle model of matter it has large spaces between them and does not have a definite shape

3 0
2 years ago
Which of the answer choices correctly describes Le Châtlier's principle?
almond37 [142]
<h3><u>Answer</u>;</h3>

A. When a reaction is at chemical equilibrium, a change in the system will cause the system to shift in the direction that will balance the change and help the reaction regain chemical equilibrium.

<h3><u>Explanation</u>;</h3>
  • Le Chatelier's principle states that when a change or a "stress" is placed on a system that is at equilibrium, the system will shift in such a way to relieve that change or stress.
  • The stresses include; changing the concentration of reactants or products, altering the temperature in the system and changing the pressure of the system.
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7 0
2 years ago
Read 2 more answers
How many liters of o2 do you have if you have 5.8 moles of o2
polet [3.4K]

Answer:

130 Liters

Explanation:

if 1 mol is 22.4 L, then 5.8 mol is 130 L (129.92 but use sig figs)

3 0
3 years ago
In the laboratory you are asked to make a 0.565 m sodium bromide solution using 315 grams of water. How many grams of sodium bro
Scorpion4ik [409]

Answer : The mass of sodium bromide added should be, 18.3 grams.

Explanation :

Molality : It is defined as the number of moles of solute present in kilograms of solvent.

Formula used :

Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}

Solute is, NaBr and solvent is, water.

Given:

Molality of NaBr = 0.565 mol/kg

Molar mass of NaBr = 103 g/mole

Mass of water = 315 g

Now put all the given values in the above formula, we get:

0.565mol/kg=\frac{\text{Mass of NaBr}\times 1000}{103g/mole\times 315g}

\text{Mass of NaBr}=18.3g

Thus, the mass of sodium bromide added should be, 18.3 grams.

6 0
3 years ago
I need help ASAP! How many reactants and products are in each element according to the chemical equation above.
Len [333]

Answer:

O 4

C 1

1 sodium

3 H

Products

1 sodium

3 H

4 O

1 C

Explanation:

7 0
3 years ago
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