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3 years ago

What is the speed of light m/s

Physics

2 answers:

Ede4ka [16]3 years ago

8 0

299 792 458 meter / second

lara31 [8.8K]3 years ago

3 0

299,792,458 m/s in vacuum, somewhat less in any material medium, different in every medium.

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1. If the atomic number is 25, how many protons does it have?

ololo11 [35]

1. 25
2. 55-25 = 30

Hope this helps! :)

7 0

3 years ago

An electric field of magnitude e is measured at a distance r from a point charge q. if the charge is doubled to 2q, and the elec

pav-90 [236]

Electric field is proportional to the charge and inversely proportional to the square of distance:
$E\propto\frac{Q}{r^{2}}$
With charge 2q and distance 2r, the electric field is proportional to:
$E_{q}\propto\frac{2q}{(2r)^{2}}=\frac{2q}{4r^{2}}=\frac{1}{2}\frac{q}{r^{2}}$
The new electric field is half of that of the original measured field.

5 0

3 years ago

Could anyone help me with this?

tatiyna

Answer:

Answer is option C..

Mark as brainlist

3 0

3 years ago

What often happens to light when it travels from one medium to another

quester [9]

Answer:

Although the speed changes and wavelength changes, the frequency of the light will be constant. The frequency, wavelength, and speed are related by: The change in speed that occurs when light passes from one medium to another is responsible for the bending of light, or refraction, that takes place at an interface.

Explanation:

3 0

3 years ago

An electron is initially moving at 1.4 x 107 m/s. It moves 3.5 m in the direction of a uniform electric field of magnitude 120 N

algol13

Answer:

K.E = 15.57 x 10⁻¹⁷ J

Explanation:

First, we find the acceleration of the electron by using the formula of electric field:

E = F/q

F = Eq

but, from Newton's 2nd Law:

F = ma

Comparing both equations, we get:

ma = Eq

a = Eq/m

where,

E = electric field intensity = 120 N/C

q = charge of electron = 1.6 x 10⁻¹⁹ C

m = Mass of electron = 9.1 x 10⁻³¹ kg

Therefore,

a = (120 N/C)(1.6 x 10⁻¹⁹ C)/(9.1 x 10⁻³¹ kg)

a = 2.11 x 10¹³ m/s²

Now, we need to find the final velocity of the electron. Using 3rd equation of motion:

2as = Vf² - Vi²

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 1.4 x 10⁷ m/s

s = distance = 3.5 m

Therefore,

(2)(2.11 x 10¹³ m/s²)(3.5 m) = Vf² - (1.4 x 10⁷)²

Vf = √(1.477 x 10¹⁴ m²/s² + 1.96 x 10¹⁴ m²/s²)

Vf = 1.85 x 10⁷ m/s

Now, we find the kinetic energy of electron at the end of the motion:

K.E = (0.5)(m)(Vf)²

K.E = (0.5)(9.1 x 10⁻³¹ kg)(1.85 x 10⁷ m/s)²

4 0

3 years ago