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Strike441 [17]
3 years ago
11

Metal atoms tend to give away valence electrons when they bond with nonmetal atoms. What type of bond will form between the meta

l and nonmetal atoms and why does this bond form?
A covalent bond will form because electrons are transferred.

An ionic bond will form because electrons are transferred.

A covalent bond will form because electrons are shared.

An ionic bond will form because electrons are shared.
Chemistry
2 answers:
vampirchik [111]3 years ago
4 0

<u>Answer:</u> The correct statement is  an ionic bond will form because electrons are transferred.

<u>Explanation:</u>

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element and the element which accepts the electrons is known as electronegative element. This bond is formed between a metal and an non-metal.

A covalent bond is formed when there is sharing of electrons between the elements forming the bond. This bond is formed between two non-metals.

Hence, the correct statement is  an ionic bond will form because electrons are transferred.

7nadin3 [17]3 years ago
4 0

Answer: B) An ionic bond will form because electrons are transferred.

Explanation:

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What will be the theoretical yield of tungsten(is) ,W, if 45.0 g of WO3 combines as completely as possible with 1.50 g of H2
Anarel [89]

Answer:

35.6 g of W, is the theoretical yield

Explanation:

This is the reaction

WO₃  +  3H₂  →   3H₂O  +  W

Let's determine the limiting reactant:

Mass / molar mass = moles

45 g / 231.84 g/mol = 0.194 moles

1.50 g / 2 g/mol = 0.75 moles

Ratio is 1:3. 1 mol of tungsten(VI) oxide needs 3 moles of hydrogen to react.

Let's make rules of three:

1 mol of tungsten(VI) oxide needs 3 moles of H₂

Then 0.194 moles of tungsten(VI) oxide would need (0.194  .3) /1 = 0.582 moles (I have 0.75 moles of H₂, so the H₂ is my excess.. Then, the limiting is the tungsten(VI) oxide)

3 moles of H₂ need 1 mol of WO₃ to react

0.75 moles of H₂ would need (0.75 . 1)/3 = 0.25 moles

It's ok. I do not have enough WO₃.

Finally, the ratio is 1:1 (WO₃ - W), so 0.194 moles of WO₃ will produce the same amount of W.

Let's convert the moles to mass (molar mass  . mol)

0.194 mol . 183.84 g/mol = 35.6 g

3 0
3 years ago
Why can non polar covalent compounds dissolve in alcohol?
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Answer:

Non-polar solvents cannot dissolve polar compounds since no opposite charges exist and the polar compound is not attracted.

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7 0
2 years ago
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a sample of gas initially occupies 5.50 liter at a pressure of 0.750 atm at 13.0 C. what will the temperture change to 22.5 C an
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Answer:

The pressure will be 2.84 atm

Explanation:

The gas laws are a set of chemical and physical laws that allow us to determine the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature and moles.

Boyle's law indicates that the volume is inversely proportional to the pressure: if the pressure increases, the volume decreases and if the pressure decreases, the volume increases. Boyle's law is expressed mathematically as:

P * V = k

On the other hand, Charles's law indicates that with increasing temperature, the volume of the gas increases and with decreasing temperature, the volume of the gas decreases. That is, they are directly proportional. This is expressed mathematically as:

\frac{V}{T} =k

Finally, the Gay-Lussac law says that at constant volume, the pressure of the gas is directly proportional to its temperature. Mathematically, it is expressed as:

\frac{P}{T} =k

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

\frac{P*V}{T}=k

When you want to study two different states, an initial and a final one of a gas, you can use the following expression:

\frac{P1*V1}{T1}=\frac{P2*V2}{T2}

In this case:

  • P1= 0.750 atm
  • V1= 5.50 L
  • T1= 13 C= 286 K (being 0 C=273 K)
  • P2=?
  • V2= 1.50 L
  • T2= 22.5 C=295.5 K

Replacing:

\frac{0.750 atm*5.50 L}{286 K}= \frac{P2*1.50 L}{295.5 K}

Solving:

P2=\frac{295.5K}{1.50L} *\frac{0.750 atm*5.50 L}{286 K}

P2= 2.84 atm

<u><em>The pressure will be 2.84 atm</em></u>

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