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Svet_ta [14]
4 years ago
14

Identify limiting and excess reagents when 25g of nitrogen reacts with 25g of hydrogen. How many grams of ammonia gas are formed

in this reaction?

Chemistry
1 answer:
Makovka662 [10]4 years ago
7 0

Answer:

Nitrogen is limiting reactant while hydrogen is in excess.

Explanation:

Given data:

Mass of N₂ = 25 g

Mass of H₂ = 25 g

Mass of ammonia formed = ?

Solution:

Chemical equation:

N₂ + 3H₂    →     2NH₃

Number of moles of Nitrogen:

Number of moles = mass/ molar mass

Number of moles = 25 g/ 28 g/mol

Number of moles = 0.89 mol

Number of moles of hydrogen:

Number of moles = mass/ molar mass

Number of moles = 25 g/ 2 g/mol

Number of moles = 12.5 mol        

Now we will compare the moles of both reactant with ammonia.

                   H₂            ;             NH₃

                    3             :              2

                    12.5        :            2/3×12.5 = 8.3

                 

                   N₂            ;             NH₃

                    1              :              2

                    0.89        :            2×0.89 = 1.78

The number of moles of ammonia produced by nitrogen are less thus nitrogen is limiting reactant while hydrogen is in excess.

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3 years ago
Methane at 10 mpa and 300 k is heated at constant pressure until its volume has increased by 80 percent. determine the final tem
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When you assume that the gas is behaving ideally, the gas molecules are very far from each other that they do not have any intermolecular forces. If it behaves this way, you can assume the ideal gas equation:

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When the process goes under constant pressure (and assuming same number of moles),

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If you do not assume ideal gas, you use the compressibility factor, z. The gas equation would now become

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7 0
3 years ago
Extra Stoichiometry Practice
Irina-Kira [14]

Answer: 50. 4g

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Moles = 38.8g/ 26.982mol/g

= 1.44mol

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0.72 moles of aluminium oxide are produced from 38.8g of aluminium

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7 0
4 years ago
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