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Inessa [10]
4 years ago
10

What are the methods that are used for heat transfer

Physics
1 answer:
Roman55 [17]4 years ago
6 0

Answer:

Heat can travel from one place to another in three ways: Conduction, Convection and Radiation. Both conduction and convection require matter to transfer heat. If there is a temperature difference between two systems heat will always find a way to transfer from the higher to lower system.

Explanation:

Hope this helps

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vladimir2022 [97]

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Show that linear S.H.M is projection of a U.C.M along any of its diameter
BigorU [14]

It shows that acceleration of particle M is directly proportional to its displacement and its direction is opposite to that of displament. Thus particle M performs simple harmonic motion but M is projection of particle performing U.C.M. hence S.H.M. is projection of U.C.M. along a diameter, of circle.

4 0
3 years ago
A 55 kg cheerleader uses an oil-filled hydraulic lift to hold four 110 kg football players at a height of 1.0 m. If her piston i
AVprozaik [17]

Answer:

D = 55.2 cm

Explanation:

As we know that the total mass of the all four players is given as

M = 4\times 110

M = 440 kg

diameter of the piston of cheer leader is given as

d_1 = 16 cm

are of cross-section is given as

A_1 = \pi r^2

A_1 = \pi(0.08)^2 = 0.02 m^2

mass of the cheer leader is given as

m = 55 kg

so the pressure due to cheer leader is given as

P_{in} = \frac{mg}{A_1}

P_{in} = \frac{55 \times 9.81}{0.02}

P_{in} = 26835 Pa

Now on the other side pressure must be same

so we have

\frac{Mg}{A} + \rho gH = P_{in}

\frac{440 \times 9.8}{A} + (900)(9.8)(1) = 26835

A = 0.24 m^2

\pi r^2 = 0.24

r = 0.276 m

so diameter on the other side is given as

D = 2 r

D = 55.2 cm

8 0
3 years ago
SCIENCE HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Andrews [41]
It's by..................
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6 0
4 years ago
Water flows through a garden hose which is attached to a nozzle. The water flows through hose with a speed of 1.81 m/s and throu
Serggg [28]

Answer:

a) 17.086m

b) 0.1671 m

Explanation:

Given data: speed of water through the hose  = 1.81 m/s

through the nozzle = 18.3 m/s

We know that maximum height of an object with upward velocity v is given by,

a) H = v^2/2g

where H is the maximum height water emerges  

= 18.3^2/(2×9.8) = 17.086 m answer

b) Again,  

H = v^2/2g

= 1.81^2/(2×9.8) = 0.1671 m

6 0
3 years ago
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