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Vikki [24]
3 years ago
7

The pH of a solution is 2.60. What is the [H3O+] for the solution?

Chemistry
1 answer:
Thepotemich [5.8K]3 years ago
3 0

Answer:

2.51 x 10⁻³

Explanation:

H = - log[H₃O⁺]

∴ 2.60 = - log[H₃O⁺]

log[H₃O⁺] = -2.6.

∴ [H₃O⁺] = 2.51 x 10⁻³.

You might be interested in
Fish need about 5 ppm oxygen dissolved in water to survive. Will water with 5 mg oxygen per
Lelechka [254]

5mg in liter is 5 ppm

Explanation: 1 ppm is one part per million.

1 ppm is 1 mg is one part of million from 1 kg = 1000 000 mg

1 litre water is 1. Kg.

3 0
3 years ago
Is O2 always a double bond?
Dima020 [189]
  • O-O single bonds and H-O single bonds in \text{H}_2\text{O}_2 molecules.
  • H-O single bonds in \text{H}_2\text{O} molecules.
  • O=O double bonds in \text{O}_2 molecules.
<h3>Explanation</h3>

How many valence electrons do atoms in each molecule need for them to be stable?

  • Each H atom needs two valence electrons to be stable.
  • Each atom of an element other than H needs eight valence electron to be stable.
  • There are two H atoms and two O atoms in an  \text{H}_2\text{O}_2 molecule. Atoms in each \text{H}_2\text{O}_2 need 2 \times 1 + 2\times 2 = 6 more electrons to be stable.
  • There are two H atoms and one O atom in an \text{H}_2\text{O} molecule. Atoms in each \text{H}_2\text{O} molecule need 2 \times 1 + 2= 4 more electrons to be stable.
  • There are two O atoms in an \text{O}_2 molecule. Atoms in each \text{O}_2 molecule need 2 \times 2 = 4 more electrons to be stable.

How many chemical bonds in each molecule?

Each chemical bond adds one valence electron to each bonding atom. Each chemical bond connects two atoms. As a result, each chemical bond adds two valence electrons to the molecule.

  • Each \text{H}_2\text{O}_2 molecule needs 6 / 2 = 3 chemical bonds.
  • Each \text{H}_2\text{O} molecule needs 4 / 2 = 2 chemical bonds.
  • Each \text{O}_2 molecule needs 4 /2= 2 chemical bonds.

What chemical bonds are these? Again, each H atom needs only one more valence electron to be stable. It will share only one electron with O and form one H-O bond. The rest of the chemical bonds are between O atoms.

  • There are two H atoms in each \text{H}_2\text{O}_2 molecule, which form two H-O bonds. Two of the three chemical bonds in this molecule are H-O. The other is an O-O single bond between the two O atoms.
  • There are two H atoms in each \text{H}_2\text{O} molecule, which form two H-O bonds. Both chemical bonds in this molecule are H-O. There's no O-O bond in this molecule.
  • There is no H atom in \text{O}_2 molecules. Both chemical bonds are between O atoms. However, there are only two O atoms. There must be two chemical bonds between the two O atoms. That bond will be an O-O double bond.
3 0
3 years ago
Read 2 more answers
What is the shape of a molecule containing three covalent bonds with one unshared pair?
Schach [20]

pyramidal, if you have a molecule kit, i would strongly recommend watching a video of someone using a kit explaining the different shapes and following along. It helps a lot!

7 0
3 years ago
The cost, C C, of producing x x Totally Cool Coolers is modeled by the equation C = 0.005 x 2 − 0.25 x + 12 C=0.005x2-0.25x+12 H
neonofarm [45]

Answer:

25 coolers are need to be produce and sell in order to minimize the cost.

Explanation:

C = 0.005x^2-0.25x+12 ..[1]

Differentiating the given expression with respect to dx.

\frac{dC}{dx}=\frac{d(0.005x^2-0.25x+12)}{dx}

\frac{dC}{dx}=0.01x-0.25+0

Putting ,\frac{dC}{dx}=0

0=0.01x-0.25+0

0.01x=0.25

x = 25

Taking second derivative of expression [1]

\frac{d^2C}{dx^2}=\frac{d(0.01x-0.25)}{dx}=0.01

\frac{d^2C}{dx^2}>0 (minima)

25 coolers are need to be produce and sell in order to minimize the cost.

3 0
3 years ago
You have come down with a nasty cold and would like to understand why the virus that infected you is making you feel so lousy. W
umka21 [38]

Answer:

a) The volume is 5.236x10⁻¹³L

b) The molarity of a single virus is 1.91x10¹² mol/L

c) The molarity for a 100 virus particles is 1.91x10¹⁴ mol/L

Explanation:

a) Given:

D = diameter of the cell = 10 μm

r = radius = 10/2 = 5 μm

The volume of the spherical cell is equal:

V=\frac{4}{3} \pi r^{3} =\frac{4}{3} \pi *(5)^{3} =523.6\mu m^{3}

If 1 μm³ = 1x10⁻¹⁵L, then 523.6 μm³ = 5.236x10⁻¹³L

b) The molarity is:

M=\frac{number-of-moles}{volume-of-solution}

For a single virus within the cell

M=\frac{1}{5.236x10^{-13} } =1.91x10^{12} mol/L

c) For a 100 virus particles the molarity is:

M=\frac{100}{5.236x10^{-13} } =1.91x10^{14} mol/L

4 0
3 years ago
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