Answer:
The concentration of HI present at equilibrium is 0.471 M.
Explanation:
We would use miles to measure the diameter of the earth because that is the greatest measure of length that is possible to measure something large.
Answer:
a) C6H5COOH + H2O ↔ H3O+ + C6H5COO-
b) [ H3O+ ] = 2.517 E-3 M
c) pH = 2.599
Explanation:
a) balanced equation:
C6H5COOH + H2O ↔ H3O+ + C6H5COO-
⇒ Ka = ( [ H3O+ ] * [ C6H5COO- ] ) / [ C6H5COOH ] = 6.5 E-5
mass balance:
0.10 m = [ C6H5COO- ] + [ C6H5COOH ].....(1)
charge balance:
[ H3O+ ] = [ C6H5COO- ] + [ OH- ] .......[ OH- ] : comes from water, it's not significant
⇒ [ H3O+ ] = [ C6H5COO- ] .........(2)
b) (2) in (1):
⇒ 0.10 M = [ H3O+ ] + [ C6H5COOH ]
⇒ [ C6H5COOH ] = 0.10 - [ H3O+ ]
⇒ Ka = [ H3O+ ]² / ( 0.1 - [ H3O+ ] ) = 6.5 E-5
⇒ [ H3O+ ]² + 6.5 E-5 [ H3O+ ] - 6.5 E-6 = 0
⇒ [ H3O+ ] = 2.517 E-3 M
c) pH = - log [ H3O+ ]
⇒ pH = - Log ( 2.517 E-3 )
⇒ pH = 2.599
Aldol condensation involves two aldehydes or two ketones or an aldehyde and a ketone. The product of the reaction is shown in the image attached.
<h3>What is Aldol condensation?</h3>
Aldol condensation is a reaction that involves two aldehydes or two ketones or an aldehyde and a ketone. This reaction occurs at the carbonyl group as one of the carbonyl compounds is in the enolate form.
The product of the reaction is shown in the image attached. This gives the mechanism for the Aldol condensation of the compound 3‑methylbutanal.
Learn more about aldol condensation: brainly.com/question/9415260