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3 years ago

Can magnesium sulphate be used for water coagulation

1 answer:

3 0

Yes it can cause you put epsom salt in a bath and theirs magnesium in that and it’s good for your body and takes fat from your body

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What volume of 0.305 m agno3 is required to react exactly with 155.0 ml of 0.274 m na2so4 solution? hint: you will want to write

LuckyWell [14K]

The balanced chemical equation for reaction of $AgNO_{3}$ and $Na_{2}SO_{4}$ is as follows:

$2 AgNO_{3}+Na_{2}SO_{4}\rightarrow 2NaNO_{3}+Ag_{2}SO_{4}$

From the balanced chemical equation, 2 mol of $AgNO_{3}$ reacts with 1 mol of $NaNO_{3}$ .

First calculating number of moles of $NaNO_{3}$ as follows:

$M=\frac{n}{V}$

On rearranging,

$n=M\times V$

Here, M is molarity and V is volume. The molarity of $NaNO_{3}$ is given 0.274 M or mol/L and volume 155 mL, putting the values,

$n=0.274 mol/L\times 155\times 10^{-3}mL=0.04247 mol$

Since, 1 mol of $NaNO_{3}$ reacts with 2 mol of $AgNO_{3}$ thus, number of moles of $AgNO_{3}$ will be $2\times 0.04247 mol=0.08494 mol$ .

Now, molarity of $AgNO_{3}$ is given 0.305 M or mol/L thus, volume can be calculated as follows:

$V=\frac{n}{M}=\frac{0.08494 mol}{0.305 mol/L}=0.2785 L=278.5 mL$

Therefore, volume of $AgNO_{3}$ is 278.5 mL.

4 0

3 years ago

I dont get dependent and independent variables if someone can explain it and give an example that wpould be great!

Musya8 [376]

An independent variable is the variable that is changed or controlled in a experiment to test the effects on the dependent variable. A dependent variable is the variable being tested and measured. so like is math. the input variable is the independent variable. the output is the dependent variable because it depends on the input variables.

5 0

3 years ago

Name four products of incomplete combustion One : Two : Three : Four :

melamori03 [73]

Answer:

Carbon Monoxide / Carbon Dioxide / Sulfur and Nitrogen Dioxide

Explanation:

8 0

3 years ago

Which pair of elements would most likely bond to form a covalently bonded compound?

anastassius [24]

Answer:

two nonmetal elements join together to form covalent compounds

3 0

3 years ago

Which of the following properties would be the same among isotopes of the same element?

Viefleur [7K]

Answer : The properties which would be the same among isotopes of the same element are Flammability and Color

Explanation :

Isotopes are the elements that have same number of electrons and protons but they differ in number of neutrons.

The chemical properties of an element are determined by its valence electrons and since isotope have same number of electrons, they have similar chemical properties.

But isotopes have different number of neutrons. Neutrons are the subatomic particles which are present in the nucleus. They are charge less particles and they have mass. Therefore when the elements have different number of neutrons, their atomic masses differ.

As a result, isotopes have different mass related physical properties.

Let us discuss the given properties now

1) Flammability : Flammability in simple words means the ability of the substance to catch fire or the ability to burn. This is mainly dependent on the reactivity which is in turn dependent on the number of electrons.

Since the isotopes have same number of electrons, they show similar flammability.

2) Density : Density is defined as mass per unit volume. This property involves mass and we know that isotopes have different masses. Therefore they have different densities too.

3) Melting point : Melting point is a physical property which is mainly dependent on the molecular weight of the substance. Since isotopes have different masses, they tend to show different melting points.

4) Color : The color of the element is mainly dependent on the arrangement of electrons around the nucleus. Isotopes have same number of electrons which means the arrangement would also be the same. Therefore the isotopes of the same element do not show different colors.

The properties which would be same among isotopes of the same element are

1) Flammability

4) Color

5 0

3 years ago