A sinusoidal wave is traveling on a string with speed 19.3 cm/s. The displacement of the particles of the string at x = 6.0 cm i
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The electric field produced by a large flat plate with uniform charge density on its surface can be found by using Gauss law, and it is equal to
where
is the charge density
is the vacuum permittivity
We see that the intensity of the electric field does not depend on the distance from the plate. Therefore, the strenght of the electric field at 4 cm from the plate is equal to the strength of the electric field at 2 cm from the plate:
where
We see that the intensity of the electric field does not depend on the distance from the plate. Therefore, the strenght of the electric field at 4 cm from the plate is equal to the strength of the electric field at 2 cm from the plate:
Answer:
Width of sound beam is 7.557 m
Explanation:
First we will calculate the wave length from given data:
λ=v/f
Were:
v is the speed
f is the frequency
We considered the opening long and narrow, Using single slit diffraction formula:
mλ=dsinΘ
where:
d is the crack width
m is the order
Θ is angle
Considering m=1, The angle between first minimum from center of beam is:
The width of beam is:
tanΘ=y/L
Width=7.557 m