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3 years ago

Which two terms describe the pH scale

2 answers:

8 0

Answer: a term used to describe a solution that has a value below 7 on the ph scale. ... pH 7 is neutral which is exactly in between acidic and alkaline. Alkalinity is anthing ... What is the pH scale in terms of acids and bases? it is a scale that ... The pH scale is logarithmic; the difference between two units is x10.

Explanation: it's just that simple

KengaRu [80]3 years ago

6 0

Answer:

 pH scale is a device used to measure the concentration of Hydrogen ions (H+) in the solution.

Explanation:

pH scale measurement ranges from 0 to 14 and most arrangements do fall inside this range, in spite of the fact that it's conceivable to get a pH beneath 0 or over 14.

Of which 0 to 6.9 is acidic , 7 is neutral , and 7.1 to 14 is basic. Anything underneath 7.0 is acidic, and anything above 7.0 is basic, or essential.

So By using ph scale the acidic and basic nature of the solution can be measured.

So the terms used are acidity and basicity.

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Consider the balanced equation. 2HCl + Mg MgCl2 + H2 If 40.0 g of HCl react with an excess of magnesium metal, what is the theor

Serga [27]

Answer:

Theoretical yield of hydrogen is 1.11 g

Explanation:

Balanced equation, $Mg+2HCl\rightarrow MgCl_{2}+H_{2}$

As Mg remain present in excess therefore HCl is the limiting reagent.

According to balanced equation, 2 moles of HCl produce 1 mol of $H_{2}$ .

Molar mass of HCl = 36.46 g/mol

So, 40.0 g of HCl = $\frac{40.0}{36.46}moles$ of HCl = 1.10 moles of HCl

Hence, theoretically, number of moles of $H_{2}$ are produced from 1.10 moles of HCl = $(\frac{1}{2}\times 1.10)moles=0.550moles$

Molar mass of $H_{2}$ = 2.016 g/mol

So, theoretical yield of $H_{2}$ = $(0.550\times 2.016)g=1.11g$

7 0

3 years ago

Read 2 more answers

What volume (mL) of the sweetened tea described in Example 1 contains the same amount of sugar (mol) as 10 mL of the soft drink

S_A_V [24]

The question is incomplete, the complete question is:

What volume (mL) of the sweetened tea described in Example 3.14 contains the same amount of sugar (mol) as 10 mL of the soft drink in this example. The example is attached below.

Answer: 75 mL of sweetened tea will contain the same amount of sugar as in 10 mL of soft drink

Explanation:

We first calculate the number of moles of soft drink in a volume of 10 mL

The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}$ .....(1)

Taking the concentration of soft drink from the example be = 0.375 M

Volume of solution = 10 mL

Putting values in equation 1, we get:

$0.375=\frac{\text{Moles of sugar in soft drink}\times 1000}{10}\\\\\text{Moles of sugar in soft drink}=\frac{0.375\times 10}{1000}=0.00375mol$

Calculating volume of sweetened tea:

Moles of sugar = 0.00375 mol

Molarity of sweetened tea = 0.05 M

Putting values in equation 1, we get:

$0.05=\frac{0.00375\times 1000}{\text{Volume of sweetened tea}}\\\\\text{Volume of sweetened tea}=\frac{0.00375\times 1000}{0.05}=75mL$

Hence, 75 mL of sweetened tea will contain the same amount of sugar as in 10 mL of soft drink

5 0

3 years ago

Suppose that 0.48 g of water at 25 ∘ C condenses on the surface of a 55- g block of aluminum that is initially at 25 ∘ C . If th

mamaluj [8]

Answer:

$49^oC$

Explanation:

At $25^oC$ , the heat of vaporization of water is given by:

$\Delta H^o_{vap} = 43988 J/mol\cdot \frac{1 mol}{18.016 g} = 2441.6 J/g$

The water here condenses and gives off heat given by the product between its mass and the heat of vaporization:

$Q_1 = \Delta H^o_{vap} m_w$

The block of aluminum absorbs heat given by the product of its specific heat capacity, mass and the change in temperature:

$Q_2 = c_{Al}m_{Al}(t_f - t_i)$

According to the law of energy conservation, the heat lost is equal to the heat gained:

$Q_1 = Q_2$ or:

$\Delta H^o_{vap} m_w = c_{Al}m_{Al}(t_f - t_i)$

Rearrange for the final temperature:

$\Delta H^o_{vap} m_w = c_{Al}m_{Al}t_f - c_{Al}m_{Al}t_i$

We obtain:

$\Delta H^o_{vap} m_w + c_{Al}m_{Al}t_i = c_{Al}m_{Al}t_f$

Then:

$t_f = \frac{\Delta H^o_{vap} m_w + c_{Al}m_{Al}t_i}{c_{Al}m_{Al}} = \frac{2441.6 J/g\cdot 0.48 g + 0.903 \frac{J}{g^oC}\cdot 55 g\cdot 25^oC}{0.903 \frac{J}{g^oC}\cdot 55 g} = 49^oC$

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3 years ago

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timurjin [86]

Answer:

Dalton was first with the modeling
They soon followed so the answer is D: rutherford and bohr modeled their experiments

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3 years ago

The numerator is the blank number in a fraction, while the denominator is the blank number in a fraction

tigry1 [53]

The top number of a portion is called its numerator whereas the bottom number is its denominator. So a Fraction is the quantity of shaded parts separated by the quantity of a balance of as demonstrated as follows: number of shaded parts is the numerator over the whole part which is the denominator.

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3 years ago

Which two terms describe the pH scale​

Which two terms describe the pH scale