Reaction involved in present electrochemical cell,
At Anode: Zn → Zn^2+ + 2e^2-
At cathode: Zn^2+ + 2e^2- → Zn
Net Reaction: Zn + Zn^2+ ('x' m) → Zn^2+(0.1 m) + Zn
Number of electrons involved in present electrochemical cell = n = 2
According to Nernst equation for electrochemical cell,
Ecell = -2.303
![\frac{RT}{nT} log \frac{[Zn^2+]R}{[Zn^2+]L}](https://tex.z-dn.net/?f=%20%5Cfrac%7BRT%7D%7BnT%7D%20log%20%20%5Cfrac%7B%5BZn%5E2%2B%5DR%7D%7B%5BZn%5E2%2B%5DL%7D%20%20)
= 0.014
Given: T =

, F = 96500 C, R = gas constant = 8.314J/K.mol, [Zn^2+]R = 0.1 m , Ecell = 0.014 v
∴ 0.014 = - 2.303

∴ log

=

= -2.1117
∴ log x = log(0.1) + 2.1117
∴x = 13.09 m
Answer:
A) Carbon
Explanation:
the others are wrong its A
Pretty sure the force of gravity increases as the object does.
84.24 g of water (H₂O)
Explanation:
We have the following chemical reaction:
2 H₂O → 2 H₂ + O₂
Now we calculate the number of moles of products.
number of moles = mass / molar weight
number of moles of H₂ = 50 / 2 = 25 moles
number of moles of O₂ = 75 / 32 = 2.34 moles
We see from the chemical reaction that for every 2 moles of H₂ produced there are 1 mole of O₂ produces for every 25 moles of H₂ produced there are 12.5 moles of O₂ but we only have 2.35 moles of O₂ available. The O₂ will be the limiting quantity from which we devise the following reasoning:
if 2 moles of H₂O produces 1 mole of O₂
then X moles of H₂O produces 2.34 mole of O₂
X = (2 × 2.34) / 1 = 4.68 moles of H₂O
mass = number of moles × molar weight
mass of H₂O = 4.68 × 18 = 84.24 g
Learn more about:
limiting reactant
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A.meter is the is the answer to the problem you and and if you need to know why then type back