Answer:
(a). The electric potential at 1.650 cm is
.
(b). The electric potential at 2.81 cm is
.
Explanation:
Given that,
Radius of sphere R=2.81 cm
Charge = +2.35 fC
Potential at center of sphere

(a). We need to calculate the potential at a distance r = 1.60 cm
Using formula of potential difference






The electric potential at 1.650 cm is
.
(b). We need to calculate the potential at a distance r = R
Using formula of potential difference



The electric potential at 2.81 cm is
.
Hence, This is the required solution.
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Answer:
The speed is 24 
Explanation:
A wave is a disturbance that propagates through a certain medium or in a vacuum, with transport of energy but without transport of matter.
The wavelength is the minimum distance between two successive points of the wave that are in the same state of vibration. It is expressed in units of length (m).
Frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).
The speed of propagation is the speed with which the wave propagates in the middle, that is, the magnitude that measures the speed at which the wave disturbance propagates along its displacement. Relate wavelength (λ) and frequency (f) inversely proportionally using the following equation:
v = f * λ.
In this case, λ= 8 meter and f= 3 Hz
Then:
v= 3 Hz* 8 meter
So:
v= 24 
<u><em>The speed is 24 </em></u>
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Answer: Heat will transfer from the water to the air. When a mass of air moves on a warmer surface it is heated by its base. Then thermal instability develops in the lower layers and then extends upwards. If the air initially contained inversions, these are destroyed and a strong gradient is established uniformly in the lower troposphere temperature.