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Sauron [17]
3 years ago
11

A student is given two 10g samples, each a mixture of only NaCl(s) and KCl(s) but in different proportions. Which of the followi

ng pieces of information could be used to determine which mixture has the higher proportion of KCl(s) ?
Chemistry
2 answers:
8090 [49]3 years ago
6 0

Answer:

The information that can be used to determine which mixture has the higher proportion of KCl IS INFORMATION ABOUT THE MASS OF CHLORINE IN EACH MIXTURE, THIS INFORMATION CAN BE OBTAINED BY USING THE LAW OF DEFINITE PROPORTION.

Explanation:

The law of definite proportion states that the chemical composition by mass of a chemical compound is always constant. For instance, a chemical compound that is made up of two elements will always contain the same proportions of the constituent elements regardless of the quantity of chemical that was used.

Using the law of definite proportion, we can determine the proportion of sodium and chlorine in NaCl and the proportion of potassium and chlorine in KCl if the mass of chlorine that was used is known. Based on the results obtained, one can easily determine the mixtures that has higher proportion of KCl.

LenaWriter [7]3 years ago
5 0

Answer:

The mass of  Cl  in each mixture

Explanation:

With the amount of Chlorine in the mixture, you can figure out the amount of Potassium and Souium to see which is more.

You might be interested in
What things typically are counted in multiples or fractions of moles
ololo11 [35]

Answer:

Individually well, defined identical chemically units such as molecules, ions, atoms, or electrons

Explanation:

The mole is used as the unit of measurement for substance such as molecules, ions, atoms, or electrons. One mole of a substance is equivalent to 6.02×10²³ particles of the substance. The number, 6.02 × 10²³ is known as Avogadro's number.

The particles quantified as moles are individually well, defined identical chemically units such that the mole can be used to describe a part of a substance or the whole substance consisting of several moles of the substance combined.

7 0
3 years ago
A sample of gas has an initial pressure of 1.5 atm, an initial volume of 3.0 L, and an initial temperature of 293K. If the final
Nataliya [291]

Answer:

1.9 L

Explanation:

Step 1: Given data

  • Initial pressure (P₁): 1.5 atm
  • Initial volume (V₁): 3.0 L
  • Initial temperature (T₁): 293 K
  • Final pressure (P₂): 2.5 atm
  • Final volume (V₂): ?
  • Final temperature (T₂): 303 K

Step 2: Calculate the final volume of the gas

If we assume ideal behavior, we can calculate the final volume of the gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂ / T₁ × P₂

V₂ = 1.5 atm × 3.0 L × 303 K / 293 K × 2.5 atm = 1.9 L

6 0
3 years ago
I need help with this
Lelechka [254]

Answer:

The answer is its equal to the volume of its container.

--------------------------------------------------------------------------------

I hope this helps! :)

7 0
3 years ago
The Center for Disease Control publishes articles explaining the causes of seasonal West Nile virus. Research proves mosquitoes
Goshia [24]

Answer:

The correct answer is - Mosquitoes transmit the virus as parasites which feed on the blood of host organisms and inject the virus during feeding.

Explanation:

According to the CDC, the seasonal West Nile virus is caused by the mosquitoes of freshwater transmit this disease to humans and others. These mosquitoes are feed on the birds and pick these viruses.

These viruses stick on mosquitoes and when they feed on the blood of humans they transmit these viruses by injecting viruses into the blood of humans.

4 0
3 years ago
Given the standard heats of reaction
ANTONII [103]

Answer:

Explanation:

M(s) → M (g ) + 20.1 kJ --- ( 1 )

X₂ ( g ) → 2X (g ) + 327.3 kJ ---- ( 2 )

M( s) + 2 X₂(g) → M X₄ (g ) - 98.7 kJ ----- ( 3 )

( 3 ) - 2 x ( 2 ) - ( 1 )

M( s) + 2 X₂(g) - 2 X₂ ( g ) - M(s)  → M X₄ (g ) - 98.7 kJ -  2 [ 2X (g ) + 327.3 kJ ] - M (g ) - 20.1 kJ

0 = M X₄ (g ) - 4 X (g ) - M (g ) - 773.4 kJ

4 X (g ) +  M (g ) =  M X₄ (g ) - 773.4kJ

heat of formation of M X₄ (g ) is - 773.4 kJ

Bond energy of one M - X bond =  773.4 / 4 =  193.4 kJ / mole

6 0
3 years ago
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