Answer:
BeCO3 will hydrolyze in an aqueous medium, yielding a basic solution.
Explanation:
In accord with the rules of salt hydrolysis, the cation
can hydrolyze. The anion
can also hydrolyze, given that the resulting conjugate acid is weak.
Given that both ions hydrolyze, the Ka (acid ionization constant) and Kb (Base ionization constant) of each reactant (or product [that is, the conjugate acid and base for each ion]) must be compared.
Using the web (hopefully some sort of reference table has been provided to you):
Ka (for Be^2+) = 
Kb (for CO3^2-) = 
= 
= 
The Kb > Ka, so the solution will be basic.
Hope this helps! My apologies if this answer is incorrect, I have not done this type of problem in a while.
Answer:
ΔE(work)= 692 Kj/mole e⁻ = 4.32 x 10²⁴ eV/mole e⁻
Explanation:
ΔE = hc/λ = (6.63 x 10⁻³⁴j·s)(2.99792 x 10⁸m/s)/(1.73 x 10⁻⁷m) = 1.15 x 10⁻¹⁸j/e⁻ x 6.023 x 10²³ e⁻/mole = 691,999 j/mole e⁻ = 692 Kj/mole e⁻ x 6.24 x 10²¹ eV/KJ = 4.32 x 10²⁴ eV/mole e⁻
Answer:
pH = -(log 10^-10)
= -(-10)
=10
so the solution is basic in nature
Chemistry affects all aspects of life and most natural events because all living and nonliving things are made of matter.