In this problem, we apply the equation regarding kinematics expressed as vf^2 = v0^2 + 2as vf eventually becomes zero because the ball stops in the end. a = -9.8 m/s2s = 2 metres this time
This gives initial velocity, vo equal to 6.26m/s
now 6.26-(-8.85) = 15.11m/s
change in velocity/change in time = average acceleration 15.11/(12/1000) = 1259.167 m/s^2
Answer:
T=9.4 N
Explanation:
We are given that
Mass of wire,m=16.5 g=
kg
1 kg=1000g
Length of wire,l=75 cm=
m
1 m=100 cm
Wavelength of transverse wave=
m
Frequency=
Mass per unit length=


Where
frequency of wave
=Wavelength of wave
Speed of wave=v
Using the formula




Using the formula

Hence, the tension,T=9.4 N
The answer is: [D]: "the position of the moon each month in relation to THE SUN AND THE MOON" .
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Note of interest: The origin of the word "month" was: "moon-th" — but shortened to "month" — (no coincidence!).
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Answer:
The value is 
Explanation:
From the question we are told that
The potential of the proton is 
Generally the momentum of the particle is mathematically represented as

Here e is the charge on the proton with value

m is the mass of the proton with value 
So

=> 
So the de-Broglie wavelength isis mathematically represented as

Here h is the Planck's constant with value

=> 
=>