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Nitella [24]
3 years ago
11

The electric current running through the wire coil in an electric motor exerts force directly onto

Physics
2 answers:
Sveta_85 [38]3 years ago
7 0
C) A powerful magnet
Mashcka [7]3 years ago
6 0

The correct choice is

C) a powerful magnet.

we know that a current carrying wire creates magnetic field around it. inside this magnetic field, when a magnet comes, the magnet experience magnetic force. This same thing happen in motor which is known as motor effect.

the electric current running through coil creates magnetic field which exerts the force on the permanent magnet.


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Help me with # 3 & #4 please
defon

Answer:

DveC başarılar yardı olduysam sevinirim

6 0
3 years ago
A particle of mass moves under a force given bywhere and are unit vectors in the and directions. The particle is placed at the o
krek1111 [17]

The elapsed time when the particle returns to the origin is determined from the ratio of initial velocity and acceleration of the particle.

<h3>Time of motion of the particle</h3>

The time of motion of the particle is calculated by applying Newton's second law of motion.

F = ma

F = m(v)/t

where;

  • t is time of motion of the particle
  • m is mass of the particle
  • v is velocity of the particle

a = v - u/t

v = u + at

when the particle returns to the origin, direction of u, = negative.

final velocity = 0

0 = -u + at

at = u

t = u/a

Learn more about force here: brainly.com/question/12970081

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4 0
2 years ago
On a typical clear day, the atmospheric electric field points downward and has a magnitude of approximately 103 N/C. Compare the
Nina [5.8K]

Answer:

a) FE = 0.764FG

b) a = 2.30 m/s^2

Explanation:

a) To compare the gravitational and electric force over the particle you calculate the following ratio:

\frac{F_E}{F_G}=\frac{qE}{mg}              (1)

FE: electric force

FG: gravitational force

q: charge of the particle = 1.6*10^-19 C

g: gravitational acceleration = 9.8 m/s^2

E: electric field = 103N/C

m: mass of the particle = 2.2*10^-15 g = 2.2*10^-18 kg

You replace the values of all parameters in the equation (1):

\frac{F_E}{F_G}=\frac{(1.6*10^{-19}C)(103N/C)}{(2.2*10^{-18}kg)(9.8m/s^2)}\\\\\frac{F_E}{F_G}=0.764

Then, the gravitational force is 0.764 times the electric force on the particle

b)

The acceleration of the particle is obtained by using the second Newton law:

F_E-F_G=ma\\\\a=\frac{qE-mg}{m}

you replace the values of all variables:

a=\frac{(1.6*10^{-19}C)(103N/C)-(2.2*10^{-18}kg)(9.8m/s^2)}{2.2*10^{-18}kg}\\\\a=-2.30\frac{m}{s^2}

hence, the acceleration of the particle is 2.30m/s^2, the minus sign means that the particle moves downward.

7 0
3 years ago
Why is density used to determine the identity of matter?
dedylja [7]
 a substance's density is the same at a certain pressure and temperature, and the density of one substance is usually different than another substance.
4 0
3 years ago
This back-and-forth movement of electrons is called . In contrast, the movement of electrons in one direction in a battery circu
stich3 [128]
The back-and-forth movement of electrons is called alternating current. Electrons go back and forth, the direction of their path alternates from one direction to another.

the movement of electrons in one direction is called direct current. The electrons move in a direct, single path without changing directions.
5 0
3 years ago
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